Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 10: Q 10.76 (page 1199)

The product of two consecutive odd integers is 168. Find the integers.

Short Answer

Expert verified

Therefore , the integers are

Step by step solution

01

Given information

The product of two consecutive odd integers is 168.

02

Solve the equation 

Let n = the first odd integer.

n + 2 = the next odd integer.

The product of two consecutive odd integers is 168.

The product of the first odd integer and the second odd integer is 168.

nn+2=168n2+2n=168n2+2n-168=0

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solvex2-6x+9=12.

Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared.

n2-16n

Find the dimensions of a triangle whose width is four more than six times its height and has an area of 208 square inches.

Solve the quadratic equation using square root property.

(n+5)2=32

Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared.

p2-22p
See all solutions

Recommended explanations on Math Textbooks

Calculus

Read Explanation

Probability and Statistics

Read Explanation

Mechanics Maths

Read Explanation

Decision Maths

Read Explanation

Pure Maths

Read Explanation

Logic and Functions

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free