An arrow is shot from the ground into the air at an initial speed of108ft/sec.Use the formula h=-16t2+v0tto determine when the arrow will be 180 feet from the ground . Round the nearest tenth of a second .

Short Answer

Expert verified

The result is 3.7 seconds and 3 seconds.

Step by step solution

01

Given information

The given statement in which an arrow is shot from the ground into the air at an initial speed of 108ft/sec.

The height is 180 feet.

02

Simplify the equation 

h=-16t2+v0t

The velocity v0is 108 feet per second and height is 180 feet.

Substitutes the values into the equation .

180=-16t2+108t16t2-108t+180=0simplifytheequation4t2-27t+45=0

03

Using quadratic formula to simplify the equation 

a = 4 , b = -27 and c= 45

t=--27±-272-44452×4t=27±729-7208t=27±98t=27+38,27-38t=3.7,3

At 3.7 seconds as well as at 3 seconds the arrow will be 180 feet from the ground .

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