Chapter 10: Q 221 (page 1235)

Solve quadratic equation using the square root property: $\frac{4}{3} v^{2} + 4 = 28$

Short Answer

Expert verified

The required result is $v = 3 \sqrt{2} o r - 3 \sqrt{2}$

Step by step solution

Given information

The given expression is $\frac{4}{3} v^{2} + 4 = 28$

Simplifying the equation

First subtract 4 from both side of equation

$\frac{4}{3} v^{2} = 24$

Simplify further ,

$v^{2} = 18$

Square root property

If $x^{2} = k$ and $k \geq 0$ then , $x = \sqrt{k} o r - \sqrt{k}$

$18 \geq 0$

$v = \sqrt{18} o r - \sqrt{18}$

localid="1657720344280" $v = 3 \sqrt{2} o r - 3 \sqrt{2}$

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Solve quadratic equation using the square root property: $\frac{4}{3} v^{2} + 4 = 28$

Short Answer

Step by step solution

Given information

Simplifying the equation

Square root property

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Solve quadratic equation using the square root property:43v2+4=28

Short Answer

Step by step solution

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Most popular questions from this chapter

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Solve quadratic equation using the square root property: $\frac{4}{3} v^{2} + 4 = 28$