Chapter 10: Q 222. (page 1235)

In the following exercises, solve using the Square Root Property.
$\frac{2}{3} w^{2} - 20 = 30$

Short Answer

Expert verified

The required answer is $w = 5 \sqrt{3} and w = - 5 \sqrt{3}$ .

Step by step solution

Step 1. Given information.

The given quadratic equation is:

$\frac{2}{3} w^{2} - 20 = 30$

Step 2. Solve using the quadratic equation by using Square Root Property.

$\frac{2}{3} w^{2} - 20 = 30$

Isolate the quadratic term and make its coefficient one by adding 20 to both sides,

$\frac{2}{3} w^{2} - 20 + 20 = 30 + 20 \frac{2}{3} w^{2} = 50$

Multiply both sides by $\frac{3}{2}$ ,

$\frac{2}{3} w^{2} \times \frac{3}{2} = 50 \times \frac{3}{2} w^{2} = 75$

Use Square Root Property,

$w = \pm \sqrt{75}$

Simplify the radical,

$w = \pm \sqrt{25} \sqrt{3} w = \pm 5 \sqrt{3}$

Rewrite to show two solutions,

$w = 5 \sqrt{3} and w = - 5 \sqrt{3}$

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In the following exercises, solve using the Square Root Property.
$\frac{2}{3} w^{2} - 20 = 30$

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Solve using the quadratic equation by using Square Root Property.

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In the following exercises, solve using the Square Root Property.23w2-20=30

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Solve using the quadratic equation by using Square Root Property.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Decision Maths

Logic and Functions

Discrete Mathematics

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Mechanics Maths

Study anywhere. Anytime. Across all devices.

In the following exercises, solve using the Square Root Property.
$\frac{2}{3} w^{2} - 20 = 30$