Chapter 10: Q 270 (page 1236)

Solve the quadratic equation by quadratic formula . $t^{2} + 13 t + 22 = 0$

Short Answer

Expert verified

The required result is $t = - 11, - 2$

Step by step solution

Given Information

The given equation is $t^{2} + 13 t + 22 = 0$

Write the quadratic equation in standard form and identify a,b,c.

The quadratic equation is in standard form.

So,

$a = 1, b = 13, c = 22$

Substitute the values in quadratic formula.

$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$

$t = \frac{- 13 \pm \sqrt{{(13)}^{2} - 4 (1) (22)}}{2 (1)} t = \frac{- 13 \pm \sqrt{169 - 88}}{2} t = \frac{- 13 \pm \sqrt{81}}{2} t = \frac{- 13 \pm 9}{2}$

We can write it as

$t = \frac{- 13 - 9}{2}, \frac{- 13 + 9}{2} t = \frac{- 22}{2}, \frac{- 4}{2} t = - 11, - 2$

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Solve the quadratic equation by quadratic formula . $t^{2} + 13 t + 22 = 0$

Short Answer

Step by step solution

Given Information

Write the quadratic equation in standard form and identify a,b,c.

Substitute the values in quadratic formula.

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Solve the quadratic equation by quadratic formula .t2+13t+22=0

Short Answer

Step by step solution

Given Information

Write the quadratic equation in standard form and identify a,b,c.

Substitute the values in quadratic formula.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Pure Maths

Decision Maths

Statistics

Calculus

Discrete Mathematics

Mechanics Maths

Study anywhere. Anytime. Across all devices.

Solve the quadratic equation by quadratic formula . $t^{2} + 13 t + 22 = 0$