In the following exercises, graph by using intercepts, the vertex, and the axis of symmetry.

y=x2+6x+13

Short Answer

Expert verified

The given information is:

y=x2+6x+13

Step by step solution

01

Step 1. Given information.

The given information is:

y=x2+6x+13

02

Step 2. Find the axis of symmetry and the vertex.

y=ax2+bx+cy=x2+6x+13

The value of coefficient ais positive therefore we can say that the parabola opens up.

The axis of symmetry is the line x=-b2a.

Substitute the values of a, and binto the equation.

x=-621=-3

Therefore, the axis of symmetry isx=-3.

The vertex is on the line of symmetry, so its x-coordinate will be x=-3.

Now substitute the value of xinto the equation,

y=-32+6-3+13=9-18+13=4

Therefore, the vertex is-3,4.

03

Step 3. Find the intercepts.

Now substitute xequal to 0 in the equation to find the intercept y,

y=02+60+13=0+0+13=13

Therefore, the point role="math" localid="1653843612331" 0,13 is the y-intercept.

We can see that the resultant point is right of the line of symmetry by 3 units.

Therefore the point left to the line of symmetry by 3 units is -6,-14, it is symmetric to y-intercept.


Now substitute yequal to 0 in the equation to find the intercept x,

x2+6x+13=0x=-6±62-411321x=-6±-162

There is no x-intercept because a square root is not possible for a negative number.

04

Step 4. Plot the graph.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free