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Elementary Algebra

Lynn Marecek, MaryAnne Anthony-Smith

$Math Studyset Vaia Explanations$ Math

2nd Edition · 1240 pages

ISBN: 9780998625713

Chapter 10: Q 55 (page 1166)

Explain why the given equation has no solution.
$x^{2} + 12 = 8$

Short Answer

Expert verified

As we obtain a solution of $x^{2} + 12 = 8$ as $x = \pm \sqrt{- 4}$ where $\sqrt{- 4}$ is not a real number, therefore the equation has no solution.

Step by step solution

01

Given Information.

The Given equation is $x^{2} + 12 = 8$

02

Isolate the binomial term.

$x^{2} = 8 - 12 x^{2} = - 4$

03

Use the Square Root Property.

$x = \pm \sqrt{- 4}$

Since $\sqrt{- 4}$ is not a real number.

So, the equation has no real solution.

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Most popular questions from this chapter

Solve the quadratic equation using square root property.

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