Add3pp2+4p-12+1p2+p-30.

Short Answer

Expert verified

The sum is3p2-14p-2(p+6)(p-5)(p-2).

Step by step solution

01

Given Information      

The Given expression is3pp2+4p-12+1p2+p-30.

02

Find the LCD of denominators.     

Factor the denominators.

p2+4p-12=(p+6)(p-2)

p2+p-30=(p+6)(p-5)

LCD=(p+6)(p-5)(p-2)

Rewrite the expression in factored form.

=3p(p+6)(p-2)+1(p+6)(p-5)

03

Rewrite each fraction as an equivalent fraction with the LCD.     

=3p(p-5)(p+6)(p-5)(p-2)+1(p-2)(p+6)(p-5)(p-2)

=3p2-15p(p+6)(p-5)(p-2)+p-2(p+6)(p-5)(p-2)

04

Add

Take common denominator.

=3p2-15p+p-2(p+6)(p-5)(p-2)

Simplify numerator.

3p2-14p-2(p+6)(p-5)(p-2)

=3p2-14p-2(p+6)(p-5)(p-2)

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