Chapter 8: Q 240 (page 954)

Add $\frac{- 4 b - 24}{b^{2} + b - 30} + \frac{b + 7}{5 - b}$ .

Short Answer

Expert verified

The sum is $\frac{- (b + 11)}{b - 5}$ .

Step by step solution

Given Information

The Given expression is $\frac{- 4 b - 24}{b^{2} + b - 30} + \frac{b + 7}{5 - b}$ .

Find the LCD of denominators.

Factor the denominators.

$b^{2} + b - 30 = (b + 6) (b - 5)$

$5 - b = - (b - 5)$

Rewrite the expression in factored form.

$= \frac{- 4 b - 24}{(b + 6) (b - 5)} + \frac{b + 7}{- (b - 5)}$

$= \frac{- 4 (b + 6)}{(b + 6) (b - 5)} - \frac{b + 7}{b - 5}$

LCD $= (b + 6) (b - 5)$ .

Rewrite each fraction as an equivalent fraction with the LCD.

$= \frac{- 4}{b - 5} - \frac{b + 7}{b - 5}$

Subtract

Take common denominator.

$= \frac{- 4 - b - 7}{b - 5}$

$= \frac{- (b + 11)}{b - 5}$

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Add $\frac{- 4 b - 24}{b^{2} + b - 30} + \frac{b + 7}{5 - b}$ .

Short Answer

Step by step solution

Given Information

Find the LCD of denominators.

Rewrite each fraction as an equivalent fraction with the LCD.

Subtract

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Add-4b-24b2+b-30+b+75-b.

Short Answer

Step by step solution

Given Information

Find the LCD of denominators.

Rewrite each fraction as an equivalent fraction with the LCD.

Subtract

One App. One Place for Learning.

Most popular questions from this chapter

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Study anywhere. Anytime. Across all devices.

Add $\frac{- 4 b - 24}{b^{2} + b - 30} + \frac{b + 7}{5 - b}$ .