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Elementary Algebra

Lynn Marecek, MaryAnne Anthony-Smith

$Math Studyset Vaia Explanations$ Math

2nd Edition · 1240 pages

ISBN: 9780998625713

Chapter 8: Q. 8.124 (page 974)

Solve :
$\frac{5}{y + 3} + \frac{2}{y - 3} = \frac{5}{y^{2} - 9}$

Short Answer

Expert verified

$y = 2$

Step by step solution

Step 1. Given information

$\frac{5}{y + 3} + \frac{2}{y - 3} = \frac{5}{y^{2} - 9}$

Step 2. Solving the equation by cross multiplication

$\frac{5}{y + 3} + \frac{2}{y - 3} = \frac{5}{y^{2} - 9} \frac{5 y - 15 + 2 y + 6}{y^{2} - 9} = \frac{5}{y^{2} - 9} 7 y - 9 = 5 7 y = 14 y = 2$

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Most popular questions from this chapter

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In the following exercises, use either method.

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. In this section, you learned to simplify the complex fraction $\frac{\frac{3}{x + 2}}{\frac{x}{x^{2} - 4}}$

two ways: rewriting it as a division problem multiplying the numerator and denominator by the LCD Which method do you prefer? Why?

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Solve :5y+3+2y-3=5y2-9

Short Answer

Step by step solution

Step 1. Given information

Step 2. Solving the equation by cross multiplication

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Solve :
$\frac{5}{y + 3} + \frac{2}{y - 3} = \frac{5}{y^{2} - 9}$