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Elementary Algebra

Lynn Marecek, MaryAnne Anthony-Smith

$Math Studyset Vaia Explanations$ Math

2nd Edition · 1240 pages

ISBN: 9780998625713

Chapter 9: Q. 404 (page 1108)

In the following exercises, solve.
$\sqrt{2 u - 3} + 2 = 0$

Short Answer

Expert verified

$u = 3.5$ .

Step by step solution

01

Step 1. Given information.

An equation given as $\sqrt{2 u - 3} + 2 = 0$ .

02

Step 2. Solution.

Isolate radical to one side, take square and simplify.

$\sqrt{2 u - 3} + 2 = 0 \sqrt{2 u - 3} + 2 - 2 = 0 - 2 \sqrt{2 u - 3} = - 2 {(\sqrt{2 u - 3})}^{2} = {(- 2)}^{2} 2 u - 3 = 4 2 u - 3 + 3 = 4 + 3 2 u = 7 \frac{2 u}{2} = \frac{7}{2} u = 3.5$

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Most popular questions from this chapter

Try It.

Solve: $\sqrt{y - 3} + 2 = \sqrt{4 y + 2}$

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