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Elementary Algebra

Lynn Marecek, MaryAnne Anthony-Smith

$Math Studyset Vaia Explanations$ Math

2nd Edition · 1240 pages

ISBN: 9780998625713

Chapter 9: Q. 407 (page 1108)

In the following exercises, solve.
$\sqrt{2 m + 1} + 4 = 0$

Short Answer

Expert verified

$m = 7.5$ .

Step by step solution

01

Step 1. Given information.

An equation is given as $\sqrt{2 m + 1} + 4 = 0$ .

02

Step 2. Solution.

Isolate radical to one side, take square and simplify.

$\sqrt{2 m + 1} + 4 = 0 \sqrt{2 m + 1} + 4 - 4 = 0 - 4 \sqrt{2 m + 1} = - 4 {(\sqrt{2 m + 1})}^{2} = {(- 4)}^{2} 2 m + 1 = 16 2 m + 1 - 1 = 16 - 1 2 m = 15 \frac{2 m}{2} = \frac{15}{2} m = 7.5$

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(a) Solve the equation $\sqrt{r + 4} - r + 2 = 0$

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