Chapter 9: Q. 9.147 (page 1094)

For the equation $\sqrt{x + 6} = x$ :
Part (a): Is $x = - 2$ a solution?
Part (b): Is $x = 3$ a solution?

Short Answer

Expert verified

Part (a): It is not a given solution.

Part (b): It is a given solution.

Step by step solution

Part (a) Step 1. Given information.

Consider the given equation,

$\sqrt{x + 6} = x$

Part (a) Step 2. Substitute x=2 in the given equation.

Assume $x = 2$ and substitute it in the given equation,

localid="1647877891548" $\sqrt{- 2 + 6} = - 2 \sqrt{4} = - 2 2 = - 2$

It is not possible.

Hence, it is not a solution.

Part (b) Step 1. Substitute x=3 in the given equation.

Assume $x = 3$ and substitute it in the given equation,

localid="1647877928473" $\sqrt{3 + 6} = 3 \sqrt{9} = 3 3 = 3$

It is possible.

Hence, it is a solution.

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For the equation $\sqrt{x + 6} = x$ :
Part (a): Is $x = - 2$ a solution?
Part (b): Is $x = 3$ a solution?

Short Answer

Step by step solution

Part (a) Step 1. Given information.

Part (a) Step 2. Substitute x=2 in the given equation.

Part (b) Step 1. Substitute x=3 in the given equation.

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For the equation x+6=x:Part (a): Is x=-2a solution?Part (b): Isx=3a solution?

Short Answer

Step by step solution

Part (a) Step 1. Given information.

Part (a) Step 2. Substitute x=2 in the given equation.

Part (b) Step 1. Substitute x=3 in the given equation.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Mechanics Maths

Decision Maths

Geometry

Pure Maths

Calculus

Theoretical and Mathematical Physics

Study anywhere. Anytime. Across all devices.

For the equation $\sqrt{x + 6} = x$ :
Part (a): Is $x = - 2$ a solution?
Part (b): Is $x = 3$ a solution?