Chapter 2: Q. 2.1 (page 204)

$I s y = \frac{4}{3} a s o l u t i o n o f 9 y + 2 = 6 y + 3 ?$

Short Answer

Expert verified

The given value $y = \frac{4}{3}$ is not the solution for the given equation.

Step by step solution

Step 1. Given information

The given equation is $9 y + 2 = 6 y + 3$

We have to determine the given value $y = \frac{4}{3}$ is the solution of the given equation.

Step 2. Explanation

$\begin{array}{l} S i n c e a s o l u t i o n t o a n e q u a t i o n i s a v a l u e o f thevariablethatmakestheequationtrue, \\ Beginbysubstitutingthevalueofthesolutionforthevariable. \\ Substitutey= \frac{4}{3} fory \\ \Rightarrow 9 y + 2 = 6 y + 3 \\ \Rightarrow 9 (\frac{4}{3}) + 2 = 6 (\frac{4}{3}) + 3 \\ Multiply \\ \Rightarrow 3 (4) + 2 = 2 (4) + 3 \\ \Rightarrow 12 + 2 = 8 + 3 \\ Add \\ \Rightarrow 14 = 11 \\ Sincey= \frac{4}{3} resultsinafalseequation. \\ \Rightarrow \frac{4}{3} isnotasolutiontothegivenequation. \end{array}$

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$I s y = \frac{4}{3} a s o l u t i o n o f 9 y + 2 = 6 y + 3 ?$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Explanation

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Isy=43asolutionof9y+2=6y+3?

Short Answer

Step by step solution

Step 1. Given information

Step 2. Explanation

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$I s y = \frac{4}{3} a s o l u t i o n o f 9 y + 2 = 6 y + 3 ?$