Chapter 2: Q. 216 (page 240)

In the following exercise, solve the following equations with variables and constants on both sides.
$\frac{4}{3} n + 9 = \frac{1}{3} n - 9$

Short Answer

Expert verified

The solution for the given equation is $n = - 18$

Step by step solution

Step 1. Given information

The given equation is $\frac{4}{3} n + 9 = \frac{1}{3} n - 9$

We have to solve the given equation

Step 2. Explanation

$\begin{array}{l} \Rightarrow \frac{4}{3} n + 9 = \frac{1}{3} n - 9 \\ \Rightarrow \frac{4}{3} n - \frac{1}{3} n + 9 = \frac{1}{3} n - \frac{1}{3} n - 9 (Subtract \frac{1}{3} nfromboththesides) \\ \Rightarrow \frac{4}{3} n - \frac{1}{3} n + 9 = - 9 (Simplify) \\ \Rightarrow \frac{4 n - 1 n}{3} + 9 = - 9 (TakeLCDtotheleftside) \\ \Rightarrow \frac{3 n}{3} + 9 = - 9 (Simplify) \\ \Rightarrow n + 9 = - 9 (Simplify) \\ \Rightarrow n + 9 - 9 = - 9 - 9 (Subtract9frombothsides) \\ \Rightarrow n = - 18 (Simplify) \\ Thesolutionisn=-18 \end{array}$

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In the following exercise, solve the following equations with variables and constants on both sides.
$\frac{4}{3} n + 9 = \frac{1}{3} n - 9$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Explanation

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Step by step solution

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Step 2. Explanation

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In the following exercise, solve the following equations with variables and constants on both sides.
$\frac{4}{3} n + 9 = \frac{1}{3} n - 9$