In the following exercises, translate to a system of equations and solve.

Drew burned 1800 calories Friday playing one hour of basketball and canoeing for two hours. Saturday he spent two hours playing basketball and three hours canoeing and burned 3200 calories. How many calories did he burn per hour when playing basketball?

The given data is that Drew burned 1800 calories Friday playing one hour of basketball and canoeing for two hours. Saturday he spent two hours playing basketball and three hours canoeing and burned 3200 calories.

Let the amount of calories burned by canoeing be x and amount of calories burned by basket ball be y.

Drew burned 1800 calories Friday playing one hour of basketball and canoeing for two hours that is $2x+y=1800--\left(1\right)$

Saturday he spent two hours playing basketball and three hours canoeing and burned 3200 calories that is$3x+2y=3200--\left(2\right)$

Rewrite the equation (1) by multiplying it with 2.

$$\begin{gathered} 2(2x+y)=2\left(1800\right) \\ 4x+2y=3600--\left(3\right) \end{gathered}$$

Solve the equation (2) and (3) by subtracting equation (2) from equation (3).

$$\begin{gathered} 4x+2y-3x-2y=3600-3200 \\ x=300 \end{gathered}$$

Substitute the value of x in equation (1) and simplify.

$$\begin{gathered} 2\left(300\right)+y=1800 \\ y=1200 \end{gathered}$$