In the following exercises, translate to a system of equations and solve.

A small jet can fly 1,072 miles in 4 hours with a tailwind but only 848 miles in 4 hours into a headwind. Find the speed of the jet in still air and the speed of the wind.

Short Answer

Expert verified

The speed of the jet in still air and the speed of the wind are 240 mph and 28 mph respectively.

Step by step solution

01

Step 1. Given Information  

The given data is that a small jet can fly 1,072 miles in 4 hours with a tailwind but only 848 miles in 4 hours into a headwind.

02

Step 2. Explanation  

Let x be the rate of the jet with tailwind and y be the rate of headwind.

The jet fly with tailwind for 4 hours and the distance covered is 1072 miles and the actual rate of jet is x+yand the distance covered can be expressed as 4(x+y)=1072--(1)

The jet fly with headwind for 4 hours. So, the actual rate of the jet is x-yand the distance covered is4(x-y)=848--(2)

03

Step 3. Calculation 

Solve the equations (1) and (2) by adding both the equations.

4x+4y+4x-4y=1072+8488x=1920x=240

Substitute the value of x in equation (1) to get the value of y.

4(240)+4y=10724y=1072-9604y=112y=28

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free