Chapter 5: Q. 76 (page 611)

In the following exercises, solve the systems of equations by substitution.
$- 2 x + 2 y = 6 y = - 3 x + 1$

Short Answer

Expert verified

The solution set is $(- \frac{1}{2}, \frac{5}{2})$ .

Step by step solution

Step 1. Given Information

In the following exercises, we have to solve the systems of equations by substitution.
$- 2 x + 2 y = 6 y = - 3 x + 1$

Step 2. Putting the value of y from the second equation in the first equation .

$- 2 x + 2 (- 3 x + 1) = 6 - 2 x - 6 x + 2 = 6 - 8 x + 2 = 6 Subtract 2 on both side - 8 x + 2 - 2 = 6 - 2 - 8 x = 4 Divide by - 8 on both side \frac{- 8}{- 8} x = \frac{4}{- 8} x = - \frac{1}{2}$

Step 3. Putting the value of x in the equation y=−3x+1.

$y = - 3 (- \frac{1}{2}) + 1 y = \frac{3}{2} + 1 y = \frac{3}{2} + 1 \cdot \frac{2}{2} y = \frac{3}{2} + \frac{2}{2} y = \frac{3 + 2}{2} y = \frac{5}{2}$

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In the following exercises, solve the systems of equations by substitution.
$- 2 x + 2 y = 6 y = - 3 x + 1$

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Putting the value of y from the second equation in the first equation .

Step 3. Putting the value of x in the equation y=−3x+1.

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In the following exercises, solve the systems of equations by substitution.−2x+2y=6y=−3x+1

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Putting the value of y from the second equation in the first equation .

Step 3. Putting the value of x in the equation y=−3x+1.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Probability and Statistics

Decision Maths

Pure Maths

Calculus

Mechanics Maths

Logic and Functions

Study anywhere. Anytime. Across all devices.

In the following exercises, solve the systems of equations by substitution.
$- 2 x + 2 y = 6 y = - 3 x + 1$