Weights The weights (kg) in the following table are from Data Set 1 “Body Data” in Appendix B. Results from two-way analysis of variance are also shown. Use the displayed results and use a 0.05 significance level. What do you conclude?


Female

Male

18-29

63.4

57.8

52.6

46.9

61.7

61.5

77.2

50.4

97

76.1

71.6

64.9

144.9

96.4

80.7

84.4

63.9

79

99.4

64.1

30-49

110.5

84.6

133.3

90.2

125.7

105.3

115.5

75.3

92.8

57.7

96.2

56.4

107.4

99.5

64.8

94.7

74.2

112.8

72.6

91.4

50-80

103.2

48.3

87.8

101.3

67.8

45.2

79.8

60.1

68.5

43.3

84.8

127.5

89.9

75.3

110.2

72.3

77.2

86.5

71.3

73.1

Short Answer

Expert verified

It can be concluded that there is a significant interaction effect between age and gender on the weights of the subjects.

Step by step solution

01

Given information

The ANOVA table is provided for the data given on weights (kgs) under two factors:

  • Age bracket (18-29, 30-49, and 50-80)
  • Gender (male and female)
02

Frame the statistical hypothesis for the interaction effect in the two-way analysis of variance

For the given two-way analysis of variance, the following hypotheses are set up:

Null Hypothesis: There is no interaction between the factors age and gender on weights.

Alternative Hypothesis: There is an interaction between the factors age and gender on weights.

03

Interpret the results for the interaction effect

The ANOVA output shows that the p-value corresponding to the F statistic value (under interaction) of 3.6652678 is equal to 0.0322.

Since the p-value (030322) is less than the significance level (0.05), the decision is to reject the null hypothesis.

It can be concluded that there is an interaction between the factors of age and gender on weights.

Since the interaction effect appears to be statistically significant, there is no need to test the individual effects of age and gender.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Balanced Design Does the table given in Exercise 1 constitute a balanced design? Why or why not?

Female Pulse Rates and Age Using the pulse rates of females from Data Set 1 “Body Data” in Appendix B after they are partitioned into the three age brackets of 18–25, 26–40, and 41–80, we get the following Statdisk display. Using a 0.05 significance level, test the claim that females from the three age brackets have the same mean pulse rate. What do you conclude?

Estimating Length Given below is a Minitab display resulting from two-way analysis of variance with sample data consisting of 18 different student visual estimates of the length of a classroom. The values are categorized according to sex and major (math, business, liberal arts). What do you conclude about an interaction between sex and major?

Cola Weights Identify the value of the test statistic in the display included with Exercise 1. In general, do larger test statistics result in larger P-values, smaller P-values, or P-values that are unrelated to the value of the test statistic?

Bonferroni Test Shown below are weights (kg) of poplar trees obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the table below. The data are from a study conducted by researchers at Pennsylvania State University and were provided by Minitab, Inc. Also shown are partial results from using the Bonferroni test with the sample data.

No Treatment

Fertilizer

Irrigation

Fertilizer and Irrigation

1.21

0.94

0.07

0.85

0.57

0.87

0.66

1.78

0.56

0.46

0.10

1.47

0.13

0.58

0.82

2.25

1.30

1.03

0.94

1.64

  1. Use a 0.05 significance level to test the claim that the different treatments result in the same mean weight.
  1. What do the displayed Bonferroni SPSS results tell us?
  1. Use the Bonferroni test procedure with a 0.05 significance level to test for a significant difference between the mean amount of the irrigation treatment group and the group treated with both fertilizer and irrigation. Identify the test statistic and either the P-value or critical values. What do the results indicate?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free