Critical Thinking: Is the pain medicine Duragesic effective in reducing pain? Listed below are measures of pain intensity before and after using the drug Duragesic (fentanyl) (based on data from Janssen Pharmaceutical Products, L.P.). The data are listed in order by row, and corresponding measures are from the same subject before and after treatment. For example, the first subject had a measure of 1.2 before treatment and a measure of 0.4 after treatment. Each pair of measurements is from one subject, and the intensity of pain was measured using the standard visual analog score. A higher score corresponds to higher pain intensity.

Pain Intensity Before Duragesic Treatment

1.2

1.3

1.5

1.6

8

3.4

3.5

2.8

2.6

2.2

3

7.1

2.3

2.1

3.4

6.4

5

4.2

2.8

3.9

5.2

6.9

6.9

5

5.5

6

5.5

8.6

9.4

10

7.6










Pain Intensity After Duragesic Treatment

0.4

1.4

1.8

2.9

6

1.4

0.7

3.9

0.9

1.8

0.9

9.3

8

6.8

2.3

0.4

0.7

1.2

4.5

2

1.6

2

2

6.8

6.6

4.1

4.6

2.9

5.4

4.8

4.1










Matched Pairs The methods of Section 9-3 can be used to test a claim about matched data. Identify the specific claim that the treatment is effective, then use the methods of Section 9-3 to test that claim.

Short Answer

Expert verified

It is claimed that the drug Duragesic is effective in reducing pain.

Using the methods of 9-3, it can be concluded that there is enough evidence to support the claim that the drug Duragesic is effective in reducing pain.

Step by step solution

01

Given information

The pain intensities of a group of subjects are recorded before and after using the drug Duragesic.

02

Hypotheses

It is claimed that the drug Duragesic is effective in reducing pain.

The following hypotheses are noted:

Null Hypothesis: The mean value of the pain intensity before the treatment is equal to the mean value of the pain intensity after the treatment.

\({H_0}:{\mu _d} = 0\)

Alternative Hypothesis: The mean value of the pain intensity before the treatment is greater than the mean value of the pain intensity after the treatment.

\({H_1}:{\mu _d} > 0\)

Here,\({\mu _d}\)represents the population difference in the pain intensities before and after the treatment.

The test is right-tailed.

03

Differences in the values of each matched pair

The following table shows the differences in the pain intensities before and after the treatment:

Before treatment

After treatment

Differences

1.2

0.4

0.8

1.3

1.4

-0.1

1.5

1.8

-0.3

1.6

2.9

-1.3

8

6

2

3.4

1.4

2

3.5

0.7

2.8

2.8

3.9

-1.1

2.6

0.9

1.7

2.2

1.8

0.4

3

0.9

2.1

7.1

9.3

-2.2

2.3

8

-5.7

2.1

6.8

-4.7

3.4

2.3

1.1

6.4

0.4

6

5

0.7

4.3

4.2

1.2

3

2.8

4.5

-1.7

3.9

2

1.9

5.2

1.6

3.6

6.9

2

4.9

6.9

2

4.9

5

6.8

-1.8

5.5

6.6

-1.1

6

4.1

1.9

5.5

4.6

0.9

8.6

2.9

5.7

9.4

5.4

4

10

4.8

5.2

7.6

4.1

3.5

The number of pairs is equal to\(n = 31\).

The mean value of the differences is computed below:

\(\begin{aligned} \bar d &= \frac{{0.8 + \left( { - 0.1} \right) + ...... + 3.5}}{{31}}\\ &= 1.38\end{aligned}\)

The standard deviation of the differences is computed below:

\(\begin{aligned} {s_d} &= \sqrt {\frac{{\sum\limits_{i = 1}^n {{{({d_i} - \bar d)}^2}} }}{{n - 1}}} \\ &= \sqrt {\frac{{{{\left( {0.8 - 1.38} \right)}^2} + {{\left( {\left( { - 0.1} \right) - 1.38} \right)}^2} + ....... + {{\left( {3.5 - 1.38} \right)}^2}}}{{31 - 1}}} \\ &= 2.92\end{aligned}\)

The mean value of the differences for the population of matched pairs \(\left( {{\mu _d}} \right)\) is considered to be equal to 0.

04

Compute the test statistic, critical value and the p-value

The value of the test statistic is computed as shown:

\(\begin{array}{c}t = \frac{{\bar d - {\mu _d}}}{{\frac{{{s_d}}}{{\sqrt n }}}}\\ = \frac{{1.38 - 0}}{{\frac{{2.92}}{{\sqrt {31} }}}}\\ = 2.623\end{array}\)

The degrees of freedom are computed below:

\(\begin{array}{c}df = n - 1\\ = 31 - 1\\ = 30\end{array}\)

The critical value of t at\(\alpha = 0.05\)and degrees of freedom equal to 30 for a right-tailed test is equal to 1.6973.

The corresponding p-value is equal to 0.0068.

05

Decision and conclusion of the test

Since the value of the test statistic (2.623) is greater than the critical value and the p-value is less than 0.05, the null hypothesis is rejected.

There is enough evidence to conclude that the drug Duragesic is effective in reducing pain.

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Most popular questions from this chapter

In exercise 10-1 12. Clusters Refer to the following Minitab-generated scatterplot. The four points in the lower left corner are measurements from women, and the four points in the upper right corner are from men.

a. Examine the pattern of the four points in the lower left corner (from women) only, and subjectively determine whether there appears to be a correlation between x and y for women.

b. Examine the pattern of the four points in the upper right corner (from men) only, and subjectively determine whether there appears to be a correlation between x and y for men.

c. Find the linear correlation coefficient using only the four points in the lower left corner (for women). Will the four points in the upper left corner (for men) have the same linear correlation coefficient?

d. Find the value of the linear correlation coefficient using all eight points. What does that value suggest about the relationship between x and y?

e. Based on the preceding results, what do you conclude? Should the data from women and the data from men be considered together, or do they appear to represent two different and distinct populations that should be analyzed separately?

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a. Construct a scatterplot.

b. Find the value of the linear correlation coefficient r, then determine whether there is sufficient evidence to support the claim of a linear correlation between the two variables.

c. Identify the feature of the data that would be missed if part (b) was completed without constructing the scatterplot.

x

10

8

13

9

11

14

6

4

12

7

5

y

9.14

8.14

8.74

8.77

9.26

8.10

6.13

3.10

9.13

7.26

4.74

Stocks and Sunspots. Listed below are annual high values of the Dow Jones Industrial Average (DJIA) and annual mean sunspot numbers for eight recent years. Use the data for Exercises 1–5. A sunspot number is a measure of sunspots or groups of sunspots on the surface of the sun. The DJIA is a commonly used index that is a weighted mean calculated from different stock values.

DJIA

14,198

13,338

10,606

11,625

12,929

13,589

16,577

18,054

Sunspot Number

7.5

2.9

3.1

16.5

55.7

57.6

64.7

79.3

z Scores Using only the sunspot numbers, identify the highest number and convert it to a z score. In the context of these sample data, is that highest value “significantly high”? Why or why not?

Coefficient of Determination Using the heights and weights described in Exercise 1, the linear correlation coefficient r is 0.394. Find the value of the coefficient of determination. What practical information does the coefficient of determination provide?

let the predictor variable x be the first variable given. Use the given data to find the regression equation and the best predicted value of the response variable. Be sure to follow the prediction procedure summarized in Figure 10-5 on page 493. Use a 0.05 significance level.

For 50 randomly selected speed dates, attractiveness ratings by males of their

female date partners (x) are recorded along with the attractiveness ratings by females of their male date partners (y); the ratings are from Data Set 18 “Speed Dating” in Appendix B. The 50 paired ratings yield\(\bar x = 6.5\),\(\bar y = 5.9\), r= -0.277, P-value = 0.051, and\(\hat y = 8.18 - 0.345x\). Find the best predicted value of\(\hat y\)(attractiveness rating by female of male) for a date in which the attractiveness rating by the male of the female is x= 8.

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