The following exercises are based on the following sample data consisting of numbers of enrolled students (in thousands) and numbers of burglaries for randomly selected large colleges in a recent year (based on data from the New York Times).

Repeat the preceding exercise, assuming that the linear correlation coefficient is r= 0.997.

Short Answer

Expert verified

Thebest predicted number of burglaries, with an enrollment of 50 (thousand), is 123.3.

The predictednumber of burglaries is obtained using the regression equation by substituting the measure of x as 50.

Step by step solution

01

Given information

A table represents the number of enrolled students (in thousands) and the number of burglaries for randomly selected large colleges in recent years.

The linear correlation coefficient is\(r = 0.997\).

From Exercise 5, the regression equation is\(\hat y = 3.83 + 2.39x\).

02

Discuss the type of model

A regression model is good if it follows the criteria stated below:

  • The scatterplot shows linear pattern.
  • The correlation coefficient measure is significant.
  • Extrapolation is not done for predicting the values.

A good model predicts the measure using the regression equation, while the predicted value of a bad model is the mean of the sampled response variables.

03

Check the type of model

The scatterplot for the samples is described below:

  • Mark enrolment on the x-axis and burglaries on the y-axis.
  • Scale the axes as per the observations.
  • Mark the paired observations on the plot.

The resultant graph is as follows.

The correlation measure is significant and the value 50 is close to the sampled enrollment data. Thus,the model is good.

04

Determine the predicted value

Using the regression equation, thebest predicted number of burglaries with an enrollment of 50 (thousand) is

\(\begin{array}{c}\hat y = 3.83 + \left( {2.39 \times 50} \right)\\ = 123.3.\end{array}\)

Therefore,thebest predicted number of burglaries with an enrollment of 50 (thousand) is 123.3.

The predicted number of burglaries for the enrollment of 50 (thousand) is obtained by substituting 50 for x in the provided regression equation.

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Most popular questions from this chapter

Outlier Refer to the accompanying Minitab-generated scatterplot. a. Examine the pattern of all 10 points and subjectively determine whether there appears to be a correlation between x and y. b. After identifying the 10 pairs of coordinates corresponding to the 10 points, find the value of the correlation coefficient r and determine whether there is a linear correlation. c. Now remove the point with coordinates (10, 10) and repeat parts (a) and (b). d. What do you conclude about the possible effect from a single pair of values?

Stocks and Sunspots. Listed below are annual high values of the Dow Jones Industrial Average (DJIA) and annual mean sunspot numbers for eight recent years. Use the data for Exercises 1–5. A sunspot number is a measure of sunspots or groups of sunspots on the surface of the sun. The DJIA is a commonly used index that is a weighted mean calculated from different stock values.

DJIA

14,198

13,338

10,606

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12,929

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Confidence Interval Construct a 95% confidence interval estimate of the mean sunspot number. Write a brief statement interpreting the confidence interval.

Explore! Exercises 9 and 10 provide two data sets from “Graphs in Statistical Analysis,” by F. J. Anscombe, the American Statistician, Vol. 27. For each exercise,

a. Construct a scatterplot.

b. Find the value of the linear correlation coefficient r, then determine whether there is sufficient evidence to support the claim of a linear correlation between the two variables.

c. Identify the feature of the data that would be missed if part (b) was completed without constructing the scatterplot.

x

10

8

13

9

11

14

6

4

12

7

5

y

9.14

8.14

8.74

8.77

9.26

8.10

6.13

3.10

9.13

7.26

4.74

Explore! Exercises 9 and 10 provide two data sets from “Graphs in Statistical Analysis,” by F. J. Anscombe, the American Statistician, Vol. 27. For each exercise,

a. Construct a scatterplot.

b. Find the value of the linear correlation coefficient r, then determine whether there is sufficient evidence to support the claim of a linear correlation between the two variables.

c. Identify the feature of the data that would be missed if part (b) was completed without constructing the scatterplot.

x

10

8

13

9

11

14

6

4

12

7

5

y

9.14

8.14

8.74

8.77

9.26

8.10

6.13

3.10

9.13

7.26

4.74

Testing for a Linear Correlation. In Exercises 13–28, construct a scatterplot, and find the value of the linear correlation coefficient r. Also find the P-value or the critical values of r from Table A-6. Use a significance level of A = 0.05. Determine whether there is sufficient evidence to support a claim of a linear correlation between the two variables. (Save your work because the same data sets will be used in Section 10-2 exercises.)

Sports Diameters (cm), circumferences (cm), and volumes (cm3) from balls used in different sports are listed in the table below. Is there sufficient evidence to conclude that there is a linear correlation between diameters and circumferences? Does the scatterplot confirm a linear association?


Diameter

Circumference

Volume

Baseball

7.4

23.2

212.2

Basketball

23.9

75.1

7148.1

Golf

4.3

13.5

41.6

Soccer

21.8

68.5

5424.6

Tennis

7

22

179.6

Ping-Pong

4

12.6

33.5

Volleyball

20.9

65.7

4780.1

Softball

9.7

30.5

477.9

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