Significance with Range Rule of Thumb. In Exercises 29 and 30, assume that different groups of couples use the XSORT method of gender selection and each couple gives birth to one baby. The XSORT method is designed to increase the likelihood that a baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5.

Gender Selection Assume that the groups consist of 16 couples.

a. Find the mean and standard deviation for the numbers of girls in groups of 16 births.

b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high.

c. Is the result of 11 girls a result that is significantly high? What does it suggest about the effectiveness of the XSORT method?

Short Answer

Expert verified

a. The mean number of girls in 16 births is equal to 8.0. The standard deviation of the number of girls in 16 births is equal to 2.0.

b. Significantly high values are equal to or above 12.0.

Significantly low values are equal to below 4.0.

Insignificant values lie between 4.0 and 12.0.

c. No, the result of 11 girls is not significantly high as it is less than 12.0;

this suggests that the XSORT method is neither extremely effective nor very incompetent in producing the desired results.

Step by step solution

01

Given information

It is given that 16 couples have tried the XSORT method to produce a baby. The probability of a girl is equal to 0.5.

02

Mean and standard deviation 

a.

Here, the probability of a girl is given to be p=0.5.

The probability of a boy is computed below:

q=1-p=1-0.5=0.5

The number of trials (n) is equal to 16.

Thus, the mean value is given as follows:

μ=np=160.5=8.0

Therefore, the mean number of girls is equal to 8.0.

The standard deviation is computed below:

σ=npq=160.50.5=2.0

Therefore, the standard deviation of the number of girls in 16 births is equal to 2.0.

03

Range rule of thumb

b.

By using the range rule of thumb, the significantly low number of girls are computed below:

μ-2σ=8.0-22.0=4.0

Thus, the significantly low number of girls is4.0 or less.

The significantly high number of girls are computed below:

μ+2σ=8.0+22.0=12.0

Thus, the significantly high number of girlsis12.0 or more.

Moreover, the values that are not significant will lie between 4.0 and 12.0.

04

Examining the significance of a value 

c.

Here, the value of 11lies between 4.0 and 12.0.

Therefore, the value of 11 girls cannot be considered significantly high as it is less than 12.0.

The value of 11 girls suggests that the XSORT method is neither very effective nor ineffective.

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Most popular questions from this chapter

In Exercises 21–24, assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an LG Smartphone survey).

If 20 adult smartphone users are randomly selected, find the probability that exactly 15 of them use their smartphones in meetings or classes.

In Exercises 15–20, refer to the accompanying table, which describes results from groups of 8 births from 8 different sets of parents. The random variable x represents the number of girls among 8 children.

Use the range rule of thumb to determine whether 1 girl in 8 births is a significantly low number of girls.

Number of girls x

P(x)

0

0.004

1

0.031

2

0.109

3

0.219

4

0.273

5

0.219

6

0.109

7

0.031

8

0.004

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0 0 1 2 17 28 21 8

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b. Find the median.

c. Find the mode.

d. Find the range.

e. Find the standard deviation.

f. Find the variance.

g. Use the range rule of thumb to identify the values separating significant values from those that are not significant.

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i. What is the level of measurement of the data: nominal, ordinal, interval, or ratio?

j. Are the data discrete or continuous?

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