In Exercises 5–20, conduct the hypothesis test and provide the test statistic and the P-value and, or critical value, and state the conclusion.

Baseball Player Births In his book Outliers, author Malcolm Gladwell argues that more baseball players have birth dates in the months immediately following July 31, because that was the age cutoff date for nonschool baseball leagues. Here is a sample of frequency counts of months of birth dates of American-born Major League Baseball players starting with January: 387, 329, 366, 344, 336, 313, 313, 503, 421, 434, 398, 371. Using a 0.05 significance level, is there sufficient evidence to warrant rejection of the claim that American-born Major League Baseball players are born in different months with the same frequency? Do the sample values appear to support Gladwell’s claim?

Short Answer

Expert verified

There is enough evidence to conclude thatbaseball players are not born with the same frequency in different months of the year.

Sample data does not support the author’s claim.

Step by step solution

01

Given information

The frequencies of baseball players born in different months are provided.

02

Check the requirements

Let O denote the observed frequencies of the players born in the 12 months.

Jan\(\left( {{O_1}} \right)\)

Feb\(\left( {{O_2}} \right)\)

March\(\left( {{O_3}} \right)\)

April\(\left( {{O_4}} \right)\)

May\(\left( {{O_5}} \right)\)

June\(\left( {{O_6}} \right)\)

387

329

366

344

336

313

July\(\left( {{O_7}} \right)\)

Aug\(\left( {{O_8}} \right)\)

Sep\(\left( {{O_9}} \right)\)

OcT\(\left( {{O_{10}}} \right)\)

Nov\(\left( {{O_{11}}} \right)\)

Dec\(\left( {{O_{12}}} \right)\)

313

503

421

434

398

371

The sum of all observed frequencies is computed below:

\(\begin{aligned}{c}n = 387 + 329 + ...... + 371\\ = 4515\end{aligned}\)

Let E denote the expected frequencies.

It is given that the number of births is expected to occur with equal frequency in all of the 12 months.

The expected frequency for each of the 12 months is the same and is equal to:

\(\begin{aligned}{c}E = \frac{{4515}}{{12}}\\ = 376.25\end{aligned}\)

As the expected value is greater than 5, the requirements for the test are satisfied.

03

State the hypotheses

The null hypothesis for conducting the given test is as follows:

\({H_0}:\)The frequency of baseball players’ births is equal in different months of the year.

The alternative hypothesis is as follows:

\({H_a}:\)The frequency of baseball players’ births is not equal in different months of the year.

The test is right-tailed.

04

Conduct the test

The table below shows the necessary calculations:

Months

O

E

\(\left( {O - E} \right)\)

\({\left( {O - E} \right)^2}\)

\(\frac{{{{\left( {O - E} \right)}^2}}}{E}\)

January

387

376.25

10.75

115.5625

0.307143

February

329

376.25

-47.25

2232.563

5.933721

March

366

376.25

-10.25

105.0625

0.279236

April

344

376.25

-32.25

1040.063

2.764286

May

336

376.25

-40.25

1620.063

4.305814

June

313

376.25

-63.25

4000.563

10.63272

July

313

376.25

-63.25

4000.563

10.63272

August

503

376.25

126.75

16065.56

42.69917

September

421

376.25

44.75

2002.563

5.322425

October

434

376.25

57.75

3335.063

8.863953

November

398

376.25

21.75

473.0625

1.257309

December

371

376.25

-5.25

27.5625

0.073256

The value of the test statistic is equal to:

\[\begin{aligned}{c}{\chi ^2} = \sum {\frac{{{{\left( {O - E} \right)}^2}}}{E}} \\ = 0.307143 + 5.933721 + ... + 0.073256\\ = 93.07176\end{aligned}\]

Thus,\({\chi ^2} = 93.072\).

Let k be the number of months, which is 12.

The degrees of freedom for\({\chi ^2}\)is computed below:

\(\begin{aligned}{c}df = k - 1\\ = 12 - 1\\ = 11\end{aligned}\)

05

State the decision

The critical value of\({\chi ^2}\)at\(\alpha = 0.05\)with 11 degrees of freedom is equal to 19.675.

The p-value is equal to 0.000.

Since the test statistic value is greater than the critical value and the p-value is less than 0.05, the null hypothesis is rejected.

06

State the conclusion

There is enough evidence to conclude thatbaseball players are not born with the same frequency in different months of the year.

The sample data for verifying the author’s claim,

August

503

September

421

October

434

November

398

December

371

Total

2127

January

387

February

329

March

366

April

344

May

336

June

313

July

313

Total

2388

The sum is higher in case of births before july 31.

Thus, it does not support the claim of the author.

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Most popular questions from this chapter

Flat Tire and Missed Class A classic story involves four carpooling students who missed a test and gave as an excuse a flat tire. On the makeup test, the instructor asked the students to identify the particular tire that went flat. If they really didn’t have a flat tire, would they be able to identify the same tire? The author asked 41 other students to identify the tire they would select. The results are listed in the following table (except for one student who selected the spare). Use a 0.05 significance level to test the author’s claim that the results fit a uniform distribution. What does the result suggest about the likelihood of four students identifying the same tire when they really didn’t have a flat tire?

Tire

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Number Selected

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In Exercises 5–20, conduct the hypothesis test and provide the test statistic and the P-value and , or critical value, and state the conclusion.

Testing a Slot Machine The author purchased a slot machine (Bally Model 809) and tested it by playing it 1197 times. There are 10 different categories of outcomes, including no win, win jackpot, win with three bells, and so on. When testing the claim that the observed outcomes agree with the expected frequencies, the author obtained a test statistic of\({\chi ^2} = 8.185\). Use a 0.05 significance level to test the claim that the actual outcomes agree with the expected frequencies. Does the slot machine appear to be functioning as expected?

The table below includes results from polygraph (lie detector) experiments conducted by researchers Charles R. Honts (Boise State University) and Gordon H. Barland (Department of Defense Polygraph Institute). In each case, it was known if the subject lied or did not lie, so the table indicates when the polygraph test was correct. Use a 0.05 significance level to test the claim that whether a subject lies is independent of the polygraph test indication. Do the results suggest that polygraphs are effective in distinguishing between truths and lies?

Did the subject Actually Lie?


No (Did Not Lie)

Yes (Lied)

Polygraph test indicates that the subject lied.


15

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Polygraph test indicates that the subject did not lied.


32

9

A study of seat belt users andnonusers yielded the randomly selected sample data summarized in the given table (based on data from “What Kinds of People Do Not Use Seat Belts?” by Helsing and Comstock, American Journal of Public Health,Vol. 67, No. 11). Test the claim that the amount of smoking is independent of seat belt use. A plausible theory is that people who smoke more are lessconcerned about their health and safety and are therefore less inclined to wear seat belts. Is this theory supported by the sample data?

Number of Cigarettes Smoked per Day

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35 and over

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175

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Don't Wear Seat Belts

149

17

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In his book Outliers,author Malcolm Gladwell argues that more

American-born baseball players have birth dates in the months immediately following July 31 because that was the age cutoff date for nonschool baseball leagues. The table below lists months of births for a sample of American-born baseball players and foreign-born baseball players. Using a 0.05 significance level, is there sufficient evidence to warrant rejection of the claim that months of births of baseball players are independent of whether they are born in America? Do the data appear to support Gladwell’s claim?


Born in America

Foreign Born

Jan.

387

101

Feb.

329

82

March

366

85

April

344

82

May

336

94

June

313

83

July

313

59

Aug.

503

91

Sept.

421

70

Oct.

434

100

Nov.

398

103

Dec.

371

82

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