A study of people who refused to answer survey questions provided the randomly selected sample data shown in the table below (based on data from “I Hear You Knocking But You Can’t Come In,” by Fitzgerald and Fuller, Sociological Methods and Research,Vol. 11, No. 1). At the 0.01 significance level, test the claim that the cooperation of

the subject (response or refusal) is independent of the age category. Does any particular age group appear to be particularly uncooperative?

Age


18-21

22-29

30-39

40-49

50-59

60 and over

Responded

73

255

245

136

138

202

Refused

11

20

33

16

27

49

Short Answer

Expert verified

The cooperation of the subject (response or refusal) is dependent on the age category.

The highest category of uncooperative subjects was in the age group of 60 and over.

Step by step solution

01

Given information

The data for the subject’s cooperation (response or refusal) and of the age category is provided.

02

Check the requirements of the test

Assume the subjects are randomly selected for the study

Use theformula for expected frequency as stated below,

\(E = \frac{{\left( {row\;total} \right)\left( {column\;total} \right)}}{{\left( {grand\;total} \right)}}\)

The observed frequency table along with row and column total is represented as,


18-21

22-29

30-39

40-49

50-59

60 and over

Row total

Responded

73

255

245

136

138

202

1049

Refused

11

20

33

16

27

49

156

Column total

84

275

278

152

165

251

1205

Theexpected frequency tableis represented as,


18-21

22-29

30-39

40-49

50-59

60 and over

Responded

73.125

239.398

242.010

132.322

143.639

218.505

Refused

10.875

35.602

35.990

19.678

21.361

32.495

Here, all expected frequencies are greater than 5, which implies the requirements of the test are satisfied.

03

State the null and alternate hypothesis

The hypotheses are formulated as follows:

\({H_0}:\)The cooperation of the subject (response or refusal) is independent of age.

\({H_1}:\)The cooperation of the subject (response or refusal) is dependent of age.

04

Compute the test statistic

The value of the test statisticis computed as,

\[\begin{aligned}{c}{\chi ^2} = \sum {\frac{{{{\left( {O - E} \right)}^2}}}{E}} \\ = \frac{{{{\left( {73 - 73.125} \right)}^2}}}{{73.125}} + \frac{{{{\left( {255 - 239.398} \right)}^2}}}{{239.398}} + ... + \frac{{{{\left( {49 - 21.361} \right)}^2}}}{{21.361}}\\ = 20.271\end{aligned}\]

Therefore, the value of the test statistic is 20.271.

05

Compute the degrees of freedom

The degrees of freedomare computed as,

\(\begin{aligned}{c}\left( {r - 1} \right)\left( {c - 1} \right) = \left( {2 - 1} \right)\left( {6 - 1} \right)\\ = 5\end{aligned}\)

Therefore, the degrees of freedom are 5.

06

Compute the critical value

From the chi-square table, the critical value for row corresponding to 5 degrees of freedom and at 0.01 level of significance 15.086.

The p-value is obtained as 0.0011.

07

State the decision

Since the critical value (15.086) is less than the value of the test statistic (20.271). In this case, the null hypothesis is rejected.

Therefore, the decision is to reject the null hypothesis.

08

State the conclusion

There is insufficient evidence to support claimthat the cooperation of the subject (response or refusal) is independent of age.

Thus, the cooperation of a subject is dependent on this age.

The proportions of subjects who were uncooperative in each category are stated below.

18-21

22-29

30-39

40-49

50-59

60 and over

Refused

0.1309\(\left( {\frac{{11}}{{84}}} \right)\)

0.0727

\(\left( {\frac{{20}}{{275}}} \right)\)

0.1187

\(\left( {\frac{{33}}{{278}}} \right)\)

0.1053

\(\left( {\frac{{16}}{{152}}} \right)\)

0.1636

\(\left( {\frac{{27}}{{165}}} \right)\)

0.1952

\(\left( {\frac{{49}}{{251}}} \right)\)

From the results, the most proportion of uncooperative subjects were in the age category 60 and over.

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Most popular questions from this chapter

Cybersecurity The accompanying Statdisk results shown in the margin are obtained from the data given in Exercise 1. What should be concluded when testing the claim that the leading digits have a distribution that fits well with Benford’s law?

Refer to the data given in Exercise 1 and assume that the requirements are all satisfied and we want to conduct a hypothesis test of independence using the methods of this section. Identify the null and alternative hypotheses.

A case-control (or retrospective) study was conductedto investigate a relationship between the colors of helmets worn by motorcycle drivers andwhether they are injured or killed in a crash. Results are given in the table below (based on datafrom “Motorcycle Rider Conspicuity and Crash Related Injury: Case-Control Study,” by Wellset al., BMJ USA,Vol. 4). Test the claim that injuries are independent of helmet color. Shouldmotorcycle drivers choose helmets with a particular color? If so, which color appears best?

Color of helmet


Black

White

Yellow/Orange

Red

Blue

Controls (not injured)

491

377

31

170

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Cases (injured or killed)

213

112

8

70

26

The table below includes results from polygraph (lie detector) experiments conducted by researchers Charles R. Honts (Boise State University) and Gordon H. Barland (Department of Defense Polygraph Institute). In each case, it was known if the subject lied or did not lie, so the table indicates when the polygraph test was correct. Use a 0.05 significance level to test the claim that whether a subject lies is independent of the polygraph test indication. Do the results suggest that polygraphs are effective in distinguishing between truths and lies?

Did the subject Actually Lie?


No (Did Not Lie)

Yes (Lied)

Polygraph test indicates that the subject lied.


15

42

Polygraph test indicates that the subject did not lied.


32

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Benford’s Law. According to Benford’s law, a variety of different data sets include numbers with leading (first) digits that follow the distribution shown in the table below. In Exercises 21–24, test for goodness-of-fit with the distribution described by Benford’s law.

Leading Digits

Benford's Law: Distributuon of leading digits

1

30.10%

2

17.60%

3

12.50%

4

9.70%

5

7.90%

6

6.70%

7

5.80%

8

5.10%

9

4.60%

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