Finding P-values. In Exercises 5–8, either use technology to find the P-value or use Table A-3 to find a range of values for the P-value.

Airport Data Speeds: The claim that for Verizon data speeds at airports, the mean. The sample size is and the test statistic is

t =-1.625 .

Short Answer

Expert verified

The p-value lies between 0.10 and 0.20.

Step by step solution

01

Given information

The claim states that the mean of data speeds is μ=14.00mbps

The sample size is n=13with the test statistic t=-1.625.

02

State the hypotheses

As per the claim, the hypotheses are stated as follows.

H0:μ=14(nullhypothesis)H1:μ14(alternativehypothesisandoriginalclaim)

Hence, it is a two-tailed test.

03

Compute the degrees of freedom 

The degrees of freedom for the given set of data are as follows.

df=n-1=13-1=12

04

Computing p-value using Table A-3

The test is a two-tailed with 12 degrees of freedom and test statistic value of

-1.625.

In Table A-3, check for the value 1.625 in the row with 12 degrees of freedom to see test statistic. The value 1.625 lies between 1.356 and 1.782.

The corresponding two-tailed area indicates the P-value between 0.10 and 0.20.

Hence, this can be written as 0.10<P-value<0.20

Thus, the range ofp-value is 0.10 and 0.20.

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Most popular questions from this chapter

Confidence interval Assume that we will use the sample data from Exercise 1 “Video Games” with a 0.05 significance level in a test of the claim that the population mean is greater than 90 sec. If we want to construct a confidence interval to be used for testing the claim, what confidence level should be used for the confidence interval? If the confidence interval is found to be 21.1 sec < μ< 191.4 sec, what should we conclude about the claim?

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69 81 39 65 42 21 60 63 66 48 64 70 96 91 65

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