P-Values. In Exercises 17–20, do the following:

a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed.

b. Find the P-value. (See Figure 8-3 on page 364.)

c. Using a significance level of \(\alpha \) = 0.05, should we reject \({H_0}\)or should we fail to reject \({H_0}\)?

The test statistic of z = 2.01 is obtained when testing the claim that \(p \ne 0.345\).

Short Answer

Expert verified

a. The test is two-tailed.

b. The p-value is equal to 0.0444.

c. The null hypothesis is rejected.

Step by step solution

01

Given Information

A test statistic value of \(z = 2.01\) is obtained, and the claim to be tested is \(p \ne 0.345\).

02

Identify the hypotheses and tail of the test

a.

In correspondence with the given claim, the following hypotheses are set up:

Null Hypothesis: \(p = 0.345\)

Alternative Hypothesis: \(p \ne 0.345\)

Since there is a not equal sign in the alternative hypothesis, the test is two-tailed.

03

P-value

b.

The test statistic to test the given claim is the z-value.

The z-value is equal to 2.01.

Using the standard normal table, the corresponding two-tailed p-value for z-score equal to 2.01 is equal to:

\(\begin{aligned}{c}2 \times P\left( {z < 2.01} \right) = 2 \times \left( {0.0222} \right)\\ = 0.0444\end{aligned}\)

Thus, the p-value is equal to 0.0444.

To depict the p-value on the normal probability graph, follow the given steps:

  • Plot a horizontal axis representing the z-score. Also, label it as “z-score”.
  • Sketch a bell-shaped curve and draw a vertical dotted line corresponding to the value “0” on the horizontal axis
  • Mark the points “-2.01” and “2.01” on the horizontal axis and then shade the area to the left of the value “-2.01” and to the right of the value “2.01” with blue as shown in the figure.
  • Label the two shaded regions as “p-value = 0.0222”.

The following plot shows the probability value (p-value) as the shaded area under the normal probability graph. Here, the sum of the two p-values corresponds to the requited two-tailed p-value (0.0444).

04

Decision about the test

c.

If the p-value is less than the level of significance, the null hypothesis is rejected; otherwise, not.

Here, the level of significance is equal to 0.05, and the p-value is equal to 0.0444.

Since the p-value is less than 0.05, the null hypothesis is rejected.

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Most popular questions from this chapter

Testing Hypotheses. In Exercises 13–24, assume that a simple random sample has been selected and test the given claim. Unless specified by your instructor, use either the P-value method or the critical value method for testing hypotheses. Identify the null and alternative hypotheses, test statistic, P-value (or range of P-values), or critical value(s), and state the final conclusion that addresses the original claim.

Car Booster Seats The National Highway Traffic Safety Administration conducted crash tests of child booster seats for cars. Listed below are results from those tests, with the measurements given in hic (standard head injury condition units). The safety requirement is that the hic measurement should be less than 1000 hic. Use a 0.01 significance level to test the claim that the sample is from a population with a mean less than 1000 hic. Do the results suggest that all of the child booster seats meet the specified requirement?

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Testing Claims About Proportions. In Exercises 9–32, test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, or critical value(s), then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Use the P-value method unless your instructor specifies otherwise. Use the normal distribution as an approximation to the binomial distribution, as described in Part 1 of this section.

Tennis Instant Replay The Hawk-Eye electronic system is used in tennis for displaying an instant replay that shows whether a ball is in bounds or out of bounds so players can challenge calls made by referees. In a recent U.S. Open, singles players made 879 challenges and 231 of them were successful, with the call overturned. Use a 0.01 significance level to test the claim that fewer than 1/ 3 of the challenges are successful. What do the results suggest about the ability of players to see calls better than referees?

A formal hypothesis test is to be conducted using the claim that the mean height of men is equal to 174.1 cm.

a. What is the null hypothesis, and how is it denoted?

b. What is the alternative hypothesis, and how is it denoted?

c. What are the possible conclusions that can be made about the null hypothesis?

d. Is it possible to conclude that “there is sufficient evidence to support the claim that the mean height of men is equal to 174.1 cm”?

df If we are using the sample data from Exercise 1 for a t-test of the claim that the population mean is greater than 90sec, What does df denote, and what is its value?

Critical Values. In Exercises 21–24, refer to the information in the given exercise and do the following.

a. Find the critical value(s).

b. Using a significance level of = 0.05, should we reject H0or should we fail to reject H0?

Exercise 18

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