P-Values. In Exercises 17–20, do the following:

a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed.

b. Find the P-value. (See Figure 8-3 on page 364.)

c. Using a significance level of = 0.05, should we reject $H_0$or should we fail to reject $H_0$?

The test statistic of z = -1.94 is obtained when testing the claim that $p=\frac{3}{8}$ .

A test statistic value of $z=-1.94$ is obtained, and the claim to be tested is $p=\frac{3}{8}$.

a.

In correspondence with the given claim, the claim cannot be considered the alternative hypothesis as it always suggests a difference in the hypothesized value and the population parameter.

The given claim is assumed to be the null hypothesis.

Thus,

Null Hypothesis: $p=\frac{3}{8}$

Alternative Hypothesis: $p\ne \frac{3}{8}$

Since there is a not-equal-to sign in the alternative hypothesis, the test is two-tailed.

b.

The test statistic to test the given claim is the z-value.

The z-value is equal to -1.94.

Using the standard normal table, the corresponding two-tailed p-value for z-score equal to -1.94 is equal to:

$$\begin{gathered} 2P\left(z<-1.94\right)=2\left(0.0262\right) \\ =0.0524 \end{gathered}$$

Thus, the p-value is equal to 0.0524.

To depict the p-value on the normal probability graph, follow the given steps:

• Plot a horizontal axis representing the z-score. Also, label it as “z-score”.
• Sketch a bell-shaped curve and draw a vertical dotted line corresponding to the value “0” on the horizontal axis
• Mark the points “-1.94” and “1.94” on the horizontal axis and then shade the area to the left of the value “-1.94” and to the right of the value “1.94” with blue as shown in the figure.
• Label the shaded regions as “p-value = 0.0262”.

The following plot shows the probability value (p-value) as the shaded area under the normal probability graph. Here, the sum of the two p-values correspond to the required two-tailed p-value (0.0524).

c.

If the p-value is less than the level of significance, the null hypothesis is rejected; otherwise, not.

Here, the level of significance is equal to 0.05, and the p-value is equal to 0.0524.

Since the p-value is greater than 0.05, so the decision is to fail to reject the null hypothesis.