Cans of coke: Confidence interval if we use the data given in exercise 1, we get this 95% confidence interval estimate of the standard deviation of volumes with the new filling process: \(0.1846 < \sigma < 0.4900\). oz. what does this confidence interval tell us about the new filling process?

The confidence interval at 95% of the standard deviation of volumes with the new filling process: \(0.1846 < \sigma < 0.4900\).

The confidence interval at a specific level of confidence is computed,

\(\sqrt {\frac{{\left( {n - 1} \right){s^2}}}{{\chi _R^2}}} < \sigma < \sqrt {\frac{{\left( {n - 1} \right){s^2}}}{{\chi _L^2}}} \)

It is inferred that the actual value of standard deviation for volumes lies between the limits \(\sqrt {\frac{{\left( {n - 1} \right){s^2}}}{{\chi _R^2}}} \)and \( < \sqrt {\frac{{\left( {n - 1} \right){s^2}}}{{\chi _L^2}}} \), which is expressed with the certain level of confidence on which confidence interval is computed.

In this case, the two limits are 0.1846 oz and 0.4900 oz.

Thus, it can be expressed with 95% confidence that the actual value of standard deviation for volumes lies between the limits 0.1846 oz and 0.4900 oz.