Using Technology. In Exercises 5–8, identify the indicated values or interpret the given display. Use the normal distribution as an approximation to the binomial distribution, as described in Part 1 of this section. Use\(\alpha \)= 0.05 significance level and answer the following:

a. Is the test two-tailed, left-tailed, or right-tailed?

b. What is the test statistic?

c. What is the P-value?

d. What is the null hypothesis, and what do you conclude about it?

e. What is the final conclusion?

Adverse Reactions to Drug The drug Lipitor (atorvastatin) is used to treat high cholesterol. In a clinical trial of Lipitor, 47 of 863 treated subjects experienced headaches (based on data from Pfizer). The accompanying TI@83/84 Plus calculator display shows results from a test of the claim that fewer than 10% of treated subjects experience headaches.

Short Answer

Expert verified

a.The test is left-tailed.

b.The value of the test statistic (z-score) is equal to -4.459.

c.The p-value is equal to 0.00000412.

d. The null hypothesis is that the proportion of treated subjects who experience headaches is equal to 10%.The null hypothesis is rejected.

e. There is enough evidence to conclude that the proportion of treated subjects who experience headaches is less than 10%.

Step by step solution

01

Given information

It is given that out of 863 subjects who were treated with the drug Lipitor, 47 of them experienced headaches. A claim is made that less than 10% of the treated subjects experience headaches.

02

Tail of the test

a.

According to the given claim, the proportion of treated subjects who experience headaches (p) is less than 10%.

Symbolically,\(p < 0.10\).

Asthere is a less than sign in the given claim, the test is left-tailed.

03

Test statistic

b.

The test statistic to test the given claim is the z-score.

Here, the value of the test statistic (z-score) is equal to -4.459.

04

P-value

c.

The p-value corresponding to the z-score of -4.459 is equal to 0.00000412 (in decimals).

05

Null hypothesis and its conclusion

d.

The null hypothesis for this test is as follows:

Null hypothesis: The proportion of treated subjects who experience headaches is equal to 10%.

Symbolically,\({H_0}:p = 0.10\),where

p is the proportion of treated subjects who suffer from headaches.

Here, the p-value equal to 0.00000412 is less than the significance level of 0.05. Thus, the null hypothesis is rejected.

06

Conclusion of the test

e.

There is enough evidence to conclude that the proportion of treated subjects who experience headaches is less than 10%.

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Most popular questions from this chapter

Testing Claims About Proportions. In Exercises 9–32, test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, or critical value(s), then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Use the P-value method unless your instructor specifies otherwise. Use the normal distribution as an approximation to the binomial distribution, as described in Part 1 of this section.

Postponing Death An interesting and popular hypothesis is that individuals can temporarily postpone death to survive a major holiday or important event such as a birthday. In a study, it was found that there were 6062 deaths in the week before Thanksgiving, and 5938 deaths the week after Thanksgiving (based on data from “Holidays, Birthdays, and Postponement of Cancer Death,” by Young and Hade, Journal of the American Medical Association, Vol. 292, No. 24). If people can postpone death until after Thanksgiving, then the proportion of deaths in the week before should be less than 0.5. Use a 0.05 significance level to test the claim that the proportion of deaths in the week before Thanksgiving is less than 0.5. Based on the result, does there appear to be any indication that people can temporarily postpone death to survive the Thanksgiving holiday?

Using Technology. In Exercises 5–8, identify the indicated values or interpret the given display. Use the normal distribution as an approximation to the binomial distribution, as described in Part 1 of this section. Use α= 0.05 significance level and answer the following:

a. Is the test two-tailed, left-tailed, or right-tailed?

b. What is the test statistic?

c. What is the P-value?

d. What is the null hypothesis, and what do you conclude about it?

e. What is the final conclusion?

Cell Phone Ownership A Pew Research Center poll of 2076 randomly selected adults showed that 91% of them own cell phones. The following Minitab display results from a test of the claim that 92% of adults own cell phones.

t Test Exercise 2 refers to a t test. What is the t test? Why is the letter t used? What is unrealistic about the z test methods in Part 2 of this section?

Critical Values. In Exercises 21–24, refer to the information in the given exercise and do the following.

a. Find the critical value(s).

b. Using a significance level of α= 0.05, should we reject H0or should we fail to reject H0?

Exercise 19

Cans of coke for the sample data from exercise 1, we get “P-value<0.01” when testing the claim that the new filling process results in volumes with the same standard deviation of 0.115 oz.

  1. What should we conclude about the null hypothesis?
  2. What should we conclude about the original claims?
  3. What do these results suggest about the new filling process?
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