Test for Normality Use the departure delay times for Flight 19 and test for normality using a normal quantile plot.

Short Answer

Expert verified

The following normal quantile plot is constructed:

As the majority of points do not lie along a straight line, the departure delay times of Flight 19 do not come from a normally distributed population.

Step by step solution

01

Given information

The departure delay times (in minutes) for Flight 19 are given.

02

Normal quantile plot

Follow the given steps to construct a normal quantile plot:

Arrange the given values in ascending order as shown:

-5

-4

-4

-1

0

1

19

73

Compute the cumulative areas to the left for each sample as follows:

Sample value

Areas to the left

-5

\(\begin{array}{c}\frac{1}{{2n}} = \frac{1}{{2\left( 8 \right)}}\\ = 0.0625\end{array}\)

-4

\(\begin{array}{c}\frac{3}{{2n}} = \frac{3}{{2\left( 8 \right)}}\\ = 0.1875\end{array}\)

-4

\(\begin{array}{c}\frac{5}{{2n}} = \frac{5}{{2\left( 8 \right)}}\\ = 0.3125\end{array}\)

-1

\(\begin{array}{c}\frac{7}{{2n}} = \frac{7}{{2\left( 8 \right)}}\\ = 0.4375\end{array}\)

0

\(\begin{array}{c}\frac{9}{{2n}} = \frac{9}{{2\left( 8 \right)}}\\ = 0.5625\end{array}\)

1

\(\begin{array}{c}\frac{{11}}{{2n}} = \frac{{11}}{{2\left( 8 \right)}}\\ = 0.6875\end{array}\)

19

\(\begin{array}{c}\frac{{13}}{{2n}} = \frac{{13}}{{2\left( 8 \right)}}\\ = 0.8125\end{array}\)

73

\(\begin{array}{c}\frac{{15}}{{2n}} = \frac{{15}}{{2\left( 8 \right)}}\\ = 0.9375\end{array}\)

The corresponding z-scores of the areas computed above are tabulated below:

Areas

z-scores

0.0625

-1.534

0.1875

-0.887

0.3125

-0.489

0.4375

-0.157

0.5625

0.157

0.6875

0.489

0.8125

0.887

0.9375

1.534

Now, plot the original data values on the x-axis and the corresponding z-scores on the y-axis.

Sample values (x)

z-scores (y)

-5

-1.534

-4

-0.887

-4

-0.489

-1

-0.157

0

0.157

1

0.489

19

0.887

73

1.534

  • Mark the values -20, 0, 20, 40, ……., 80 on the horizontal scale. Label the axis as “Sample Values”.
  • Mark the values -2.000, -1.500, -1.000, …….., 2.000 on the vertical axis. Label the axis as “z-score”.
  • Place a dot for the values of the z-scores corresponding to the sample values on the x-axis.
  • Draw a straight trend line.

The following normal quantile plot is obtained:

Since most of the points do not lie along a straight line, the departure delay times of Flight 19 do not come from a normally distributed population.

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