Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 6: Q1 (page 291)

Bone Density Test.

In Exercises 1–4, assume that scores on a bone mineral density test are normally distributed with a mean of 0 and a standard deviation of 1.

Bone Density Sketch a graph showing the shape of the distribution of bone density test scores.

Short Answer

Expert verified

The graph for the shape of distribution of bone density test scores is shown below:

Step by step solution

01

Given information

The bone mineral density test scores are normally distributed with mean value of 0 and standard deviation of 1.

02

Describe the random variable

Let Z be the random variable for bone mineral density test scores.

Z~Nμ,σ2~N0,12

The shape of the curve is expected to be bell-shaped, symmetric at mean value of 0.

03

Sketch the graph

The steps to sketch the graph are:

  1. Draw horizontal axis with values extending from –3 to 3 with a gap of 1 unit each.
  2. Sketch a bell shape curve such that it increases from –3 to 0 and then decreases smoothly from 0 to 3, maintaining symmetry at 0.

The graph is shown below:

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercises 21–24, use these parameters (based on Data Set 1 “Body Data” in Appendix B):• Men’s heights are normally distributed with mean 68.6 in. and standard deviation 2.8 in.• Women’s heights are normally distributed with mean 63.7 in. and standard deviation 2.9 in. Executive Jet Doorway the Gulfstream 100 is an executive jet that seats six, and it has a doorway height of 51.6 in.

a. What percentage of adult men can fit through the door without bending?

b. Does the door design with a height of 51.6 in. appear to be adequate? Why didn’t the engineers design a larger door?

c. What doorway height would allow 40% of men to fit without bending?

In Exercises 9–12, find the indicated IQ score and round to the nearest whole number. The graphs depict IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15 (as on the Wechsler IQ test).

Standard Normal DistributionIn Exercises 17–36, assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. In each case, draw a graph, then find the probability of the given bone density test scores. If using technology instead of Table A-2, round answers

to four decimal places.

Greater than -2.00.

Mean Absolute DeviationIs the mean absolute deviation of a sample a good statistic for estimating the mean absolute deviation of the population? Why or why not?

Finding Bone Density Scores. In Exercises 37–40 assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. In each case, draw a graph, then find the bone density test score corresponding to the given information. Round results to two decimal places.

Find the bone density scores that can be used as cutoff values separating the lowest 3% and highest 3%.
See all solutions

Recommended explanations on Math Textbooks

Pure Maths

Read Explanation

Geometry

Read Explanation

Probability and Statistics

Read Explanation

Logic and Functions

Read Explanation

Discrete Mathematics

Read Explanation

Calculus

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free