Losses to Robbery. The Federal Bureau of investigation conducts surveys to obtain information on the value of losses from various types of robberies. Results of the surveys are published in Population-at-Risk Rates and Selected Crime indicators, Independent simple random samples of reports for three types of robberies-highway, gas station, and convenience store gave the following data, in dollars, on the value of losses.

a. What does MSTR measure?

b. What does MSE measure?

c. Suppose that you want to perform a one-way ANOVA to compare the mean losses among the three types of robberies. What conditions are necessary? How crucial are those conditions?

Short Answer

Expert verified

(a) The MSTR compares the sample means of the three different types of robberies.

(b) MSE quantifies the variation among the three robberies' sample means.

(c) The first and last conditions are extremely tough to break because there is no other way to do it. If the distribution is approximately normal, the second condition, we can use one-way ANOVA. If the sample sizes are about comparable, the third criterion can be broken.

Step by step solution

01

Part (a) Step 1: Given information

The given data is

02

Part (a) Step 2: Explanation

The MSTR mean sum of squares therapy.

Losses from three different sorts of robberies.

As a result, the sum of squares mean treatment assesses the changes in the sample means.

As a result, the MSTR compares the sample means of the three different types of robberies.

03

Part (b) Step 1: Given information

The given data is

04

Part (b) Step 2: Explanation

The MSE stands for mean squared error. It calculates the changes in data samples.

As a result, MSE quantifies the variation among the three robberies' sample means.

05

Part (c) Step 1: Given information

The given data is

06

Part (c) Step 2: Explanation

The necessary conditions are

- Simple random samples,

- normal populations,

- equal standard deviations,

- independent random samples.

The first and last conditions are extremely tough to break because there is no other way to do it. If the distribution is approximately normal, the second condition, we can use one-way ANOVA. If the sample sizes are about comparable, the third criterion can be broken.

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Most popular questions from this chapter

Figure 13.7 shows side-by-side boxplots of independent samples from three normally distributed populations having equal standard deviations. Based on these boxplots, would you be inclined to reject the null hypothesis of equal population means? Why?

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b. Perform a residual analysis.

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