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Chapter 13: Q.13.38 (page 542)

Fill in the missing entries in the partially completed one-way ANOVA tables.

Short Answer

Expert verified

The completed ANOVA table is

sourcedfSSMS=SS/dfF=statisticTreatment243.30421.6523.709error1284.4007.033total14127.704

Step by step solution

01

Given Information

Given data:

02

Explanation

The degrees of freedom of the error is

errordf=totaldf-treatmentdf

=14-2

=12

SSTR (sum of squares treatment):

MSTR=SSTRk-1

SSTR=MSTR(k-1)

=21.562(2)

=43.304

03

Explanation

Calculate the error mean squares MSE:

MSE=SSEn-k

=84.40012

=7.033

Calculate the F-statistic:

F-statistics=MSTRMSE

=21.6527.033

=3.079

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Most popular questions from this chapter

In Exercise \(13.42-13.47\) we provide data from independent simple random samples from several populations. In each case,

a. compute SST, SSTR and SSE by using the computing formulas given in Formula \(13.1\) on page \(535\).

b. compare your results in part (a) for SSTR and SSE with those you obtained in Exercises \(13.24-13.29\) where you employed the defining formulas.

c. construct a one-way ANOVA table.

d. decide at the \(5%\) significance level, whether the data provide sufficient evidence to conclude that the means of the populations from which the samples were drawn are not all the same.

For an F-curve with df=(6,10), find

a. F0.05-

b. F0.01.

c. F002s-

We stated earlier that a one-way ANOVA test is always right-tailed because the null hypothesis is rejected only when the test statistic, F, is too large. Why is the null hypothesis rejected only when F is too large?

How many degrees of freedom does an F-curve have? What are those degrees of freedom called?

Following are the notations for the three sums of squares. State the name of each sum of squares and the source of variation each sum of squares represents.

a. SSE

b. SSTR

c. SST
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