a. Find the expected frequencies. Note: You will first need to compute the row totals, column totals, and grand total.

b. Determine the value of the chi-square statistic.

c. Decide at the5%significance level whether the data provide sufficient evidence to conclude that the two variables are associated.

Short Answer

Expert verified

(a) yxABTotala151530b353570Total5050100

(b) The value of the chi-square statistic =4.7619

(c)At a percent significance level, there is sufficient evidence to indicate the presence of an association between the variables and .

Step by step solution

01

part (a) Step 1: Given information:

Given in the question that, we have presented a contingency table that gives a cross-classification of a random sample of values for two variables, xand y, of a population.

We need to find the expected frequencies.

02

Part(a) Step 2: Explanation

The values of two variables xand ypicked from a random sample of a population are classified in the table below.

localid="1653738509387" yxABa1020b4030

The anticipated frequency is calculated as localid="1653738515030" E=R·Cn,where localid="1653738523116" Rrepresents the row total, localid="1653738529573" Crepresents the column total, and localid="1653738583207" nrepresents the sample size.

Determine the totals for each row and column:

localid="1653738588542" yxABTotala102030b403070Total5050100

Using the equation localid="1653738593262" E=R·C100the following table shows the computed anticipated frequencies:

yxABTotala151530b353570Total5050100

03

Part(b) Step 1: Given information

Given in the question that, we have presented a contingency table that gives a cross-classification of a random sample of values for two variables, xand y, of a population.

We need to find the value of the chi-square statistic .

04

Part (b) Step 2: Explanation

The statistics of the chi-square test

χ2=(O-E)2E,

observed frequency is O

Calculate the test statistics as follows:

χ2=(10-15)2/15+(40-35)2/35+(20-15)2/15+(30-35)2/35

=4.7619

05

Part(c) Step 1: Given information

Given in the question that, we have presented a contingency table that gives a cross-classification of a random sample of values for two variables, xand y, of a population.

We need to find that whether the data provide sufficient evidence to conclude that the two variables are associated at the5% significance level

06

Part(c) Step 2: Explanation

If the test statistic value is greater than χα2with degrees of freedom, reject the null hypothesis.

df=(r-1)(c-1)

Establish the hypotheses:

H0:The variables xand ydo not have any relationship.

Ha: The variables xand yhave a relationship

α=5%=0.05

Table can be used to determine the crucial value.Vwith df=(2-1)(2-1)=1

χ0.052=3.841

The value of the calculated test statistics

4.7619>3.841RejectH0

At a 5percent significance level, there is sufficient evidence to indicate the presence of an association between the variables x and y.

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Most popular questions from this chapter

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In each of the given Exercises, we have presented a contingency table that gives a cross-classification of a random sample of values for two variables, x, and y, of a population. For each exercise, perform the following tasks.

a. Find the expected frequencies. Note: You will first need to compute the row totals, column totals, and grand total.

b. Determine the value of the chi-square statistic.

c. Decide at the 5% significance level whether the data provide sufficient evidence to conclude that the two variables are associated.

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