The U.S. Census Bureau publishes census data on the resident population of the United States in Current Population Reports. According to that document, 7.3% of male residents are in the age group20−24 years.
a. If there is no association exists between age group and gender, what percentage of the resident population would be in the age group20−24 years? Explain your answer.
b. If there is no association exists between age group and gender, what percentage of female residents would be in the age group20−24 years? Explain your answer.
c. There are about 158million female residents of the United States. If no association exists between age group and gender, how many female residents would there be in the age group20−24 years?
d. In fact, there are some 10.2 million female residents in the age group20−24 years. Given this number and your answer to part (c), what do you conclude?

Short Answer

Expert verified

(a) If no association exists between age group and gender, 7.3%of the resident population would be in the age group 20−24 years

(b) If there is no association exists between age group and gender, 7.3% of female residents would be in the age group 20−24 years

(c)The number of female residents would there be in the age group20−24 years if there is no association exists between age group and gender is 11.534million.

(d) We can conclude that there is an association between age group and gender.

Step by step solution

01

Part (a) Step 1. Given Information.

According to that document, 7.3% of male residents are in the age group 20−24 years.

02

Part (a) Step 2. Find the percentage of the resident population.

If there is no association exists between age group and gender, then the percentage of conditional distribution of age group within the gender and the percentage of marginal age group are similar.

If no association exists between age group and gender, 7.3%of the resident population would be in the age group20−24 years

03

Part (b) Step 1. Find the percentage of female residents.

If there is no association exists between age group and gender, then the percentage of conditional distribution of age group within the gender and the conditional distribution for each gender are identical.

If there is no association exists between age group and gender,7.3% of female residents would be in the age group20−24 years

04

Part (c) Step 1. Find the number of female residents.

There are about 158 femal residents in the United States.

The number of female residents would there be in the age group 20−24 years if there is no association exists between age group and gender is given by,

=7.3%of158=11.534million.

05

Part (d) Step 1. Conclusion from Part (c).

The number of female residents would there be in the age group 20−24 years if there is no association exists between age group and gender is 11.534 million which is not same as the given number of female residents would there be in a age group of 20-24years of age.

We can conclude that there is an association between age group and gender.

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Most popular questions from this chapter

School Enrollment. Refer to Exercise 12:48. For students below postsecondary, solve the following problems.

a. Determine the conditional distribution of level for each gender.

b. Determine the marginal distribution of level.

c. Are the variables "gender"" and "level" associated? Explain your answer

d. Find the percentage of students in nursery school.

e. Find the percentage of females in nursery school.

f. Without doing any further calculations, respond true or false to the following statement and explain your answer: "The conditional distributions of gender within levels are not identical " .

g. Determine and interpret the marginal distribution of gender and the conditional distributions of gender within levels.

We have presented a contingency table that gives a cross-classification of a random sample of values for two variables x and y, of a population.

Perform the following tasks

a. Find the expected frequencies Note: You will first need to compute the row totals, column totals, and grand total.

b. Determine the value of the chi-square statistic

c. Decide at the 5% significance level whether the data provide sufficient evidence to conclude that the two variables are associated.

Education of Prisoners. In the article "Education and Correctional Populations" (Bureau of Justice Statistics Special Report, NCJ 195670), C. Harlow examined the educational attainment of prisoners by type of prison facility. The following contingency table was adapted from Table 1 of the article. Frequencies are in thousands, rounded to the nearest hundred.


StateFederalLocalTotal
8th grade or less149.910.666.0226.5
some high school269.112.9168.2450.2
GED300.820.171.0391.9
High school diploma216.424.0130.4370.8
Postsecondary95.014.051.9160.9
College grad and more25.37.216.148.6
Total1056.588.8503.61648.9

How many prisoners

a. are in state facilities?

b. have at least a college education?

c. are in federal facilities and have at most an 8th-grade education?

d. are in federal facilities or have at most an 8th-grade education? e. in local facilities have a postsecondary educational attainment

f. who have a postsecondary educational attainment are in local facilities?

g. are not in federal facilities?

In each of the given Exercises, we have given the number of possible values for two variables of a population. For each exercise, determine the maximum number of expected frequencies that can be less than 5 in order that Assumption 2 of Procedure 12.2 on page 506 to be satisfied. Note: The number of cells for a contingency table with m rows and n columns is m⋅n.

12.69 four and five

In each of the given Exercises, we have given the number of possible values for two variables of a population. For each exercise, determine the maximum number of expected frequencies that can be less than 5 in order that Assumption 2 of Procedure 12.2 on page 506 to be satisfied. Note: The number of cells for a contingency table with m rows and n columns is m⋅n.

12.73 two and two

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