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Chapter 12: Q. 12.97 (page 518)
Fill in the blank: If a variable has only two possible values, the chi-square homogeneity test provides a procedure for comparing several population......................................
Fill in the blank: Proportions
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In each of the given Exercises, we have given the number of possible values for two variables of a population. For each exercise, determine the maximum number of expected frequencies that can be less than 5 in order that Assumption 2 of Procedure 12.2 on page 506 to be satisfied. Note: The number of cells for a contingency table with m rows and n columns is m⋅n.
12.71 two and three
Although the chi-square homogeneity test and the chi-square independence test use essentially the same basic procedure, the context of the two tests are quite different. Explain the difference.
Why is the phrase "goodness of fit" used to describe the type of hypothesis test considered in this section?
The -table has entries for areas of and. In contrast, the -table has entries for those areas and for and Explain why the -values corresponding to these additional areas can be obtained from the existing -table but must be provided explicitly in the -table.
In each of Exercises 12.11-12.16, we have given the relative frequencies for the null hypothesis of a chi-square goodness-of-fir text and the sample size. In each case, decide whether Assumptions 1 and 2 for using that text are satisfied.
Sample size : n= 50.
Relative frequencies: 0.22 , 0.21 , 0.25 , 0.30 , 0.02.
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