For a $f-$curve with $\mathrm{df}=6$, use Table IV to find each $f-$value.

a. $t_{0.10}$

b. $t_{0.025}$

c. $f_{0.01}$

A f-curve with $\mathrm{df}=6$.

$t_{0.10}$To find the value of $t_{0.10}$ for $t_{0.10}$

Because there are $6$ degrees of freedom, we begin in table-IV by going along the outside columns, designated df, to "$6$" Then we get to $1.440$ by traversing across that row to the column labelled $t_{0.10}$

$\therefore f_{w}df=6,t_{0.10}=1.440$

To find the value of $t_{0.025}$for $df=6$

The number of degrees of freedom is $6$, hence in table IV, we go along the outside columns labelled df to "$6$" Then we get to $2.447$by traversing across that row to the column labelled $t_{0.025}$

$\therefore$ For $df=6,t_{0.025}=2.447$

To find the value of $t_{0.01}$for $df=6$

Because there are $6$ degrees of freedom, we begin in table-IV by going along the outside columns, designated df, to "$6$" Then we reach $3.143$ by continuing across that row to the column labelled$t_{0.01}$

$\therefore \text{For}df=6,t_{0.01}=3.143$