New Mobile Homes. Refer to Examples 8.1 and 8.2 Use the data in Table 8.1 on page 315 to obtain a 68% confidence interval for the mean price of all new mobile homes. (Hint: Proceed as in Example 8.2, but use Property 1 of the empirical rule on page 271 instead of Property 2 .)

Short Answer

Expert verified

The mean price of all new mobile homes (μ) lie within the 68% confidence interval obtained.

Step by step solution

01

Given information

n=36and x¯=63.28

02

Concept

The formula used:x¯±1σn

03

Explanation

Using Property 1., calculate a 68%confidence interval for the mean price of all new mobile homes.

From Examples 8.1and 8.1,n=36and x¯=63.28

Empirical rule:

Property 1: Around 68%of the data set is located between (x¯-s,x¯+s)

Property 2: Approximately 95%of the data set is located between

(x¯-2s,x¯+2s)

Property 3: Approximately 99.7%of the data set is located between

(x¯-3s,x¯+3s)

Using Property 1, 68 percent of the observations are within one standard deviation of the mean on either side.

04

Calculation

The 95%confidence interval for the population mean is,

x¯±1σn=63.28±1(7.2)36=63.28±1.2=(63.28-1.2,63.28+1.2)=(62.08,64.48)

By considering Property 1,the 68percent confidence interval for the mean price of all new mobile homes is (62.08,64.48)

As a result, the (μ) mean price of all new mobile homes falls within the 68% confidence interval.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Explain the effect on the margin of error and hence the effect on the accuracy of estimating a population mean by a sample mean.

Decreasing the sample size while keeping the same confidence level.

A confidence interval for a population mean has a margin of error of 0.047

a. Determine the length of the confidence interval.

b. If the sample mean is 0.205, obtain the confidence interval.

c. Construct a graph that illustrates your results.

Assume that the population standard deviation is known and decide weather use of the zinterval procedure to obtain a confidence interval for the population mean is reasonable. Explain your answers.

The variable under consideration is very close to being normally distributed, and the sample size is75.

"Chips Ahoy! 1,000 Chips Challenge." As reported by B. Warner and J. Rutledge in the paper "Checking the Chips Ahoy! Guarantee" (Chanee, Vol. 12. Issue 1. pp. 10-14), a random sample of forty-two 18-ounce bags of Chips Ahoy! cookies yielded a mean of 1261.6 chips per bag with a standard deviation of 117.6 chips per bug.

a. Determine a 95% confidence interval for the mean number of chips per bag for all 18-ounce bags of Chips Ahoy! cookies, and interpret your result in words.

b. Can you conclude that the average 18-ounce bag of Chips Ahoy! cookies contain at least 1000 chocolate chips? Explain your answer.

Class Project: Gestation Periods of Humans. This exercise can be done individually or, better yet, as a class project. Gestation periods of humans are normally distributed with a mean of 266 days and a standard deviation of 16 days.

a. Simulate 100 samples of nine human gestation periods each.

b. For each sample in part (a), obtain a 95% confidence interval for the population mean gestation period.

c. For the 100 confidence intervals that you obtained in part (b), roughly how many would you expect to contain the population mean gestation period of 266 days?

d. For the 100 confidence intervals that you obtained in part (b), determine the number that contain the population mean gestation period of 266 days.

e. Compare your answers from parts (c) and (d), and comment on any observed difference.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free