Toxic Mushrooms?Cadmium, a heavy metal, is toxic to animals. Mushrooms, however, are able to absorb and accumulate cadmium at high concentrations. The Czech and Slovak governments have set a safety limit for cadmium in dry vegetables at 0.5part per million (ppm). M. Melgar et al. measured the cadmium levels in a random sample of the edible mushroom Bolefus pinicola and published the results in the paper "Influence of Some Factors in Toxicity and Accumulation of Cd from Edible Wild Macrofungi in NW Spain (Journal of Envionmental Science and Health. Here are the data obtained by the researchers.

Find and interpret a 99%confidence interval for the mean cadmium level of all Boletus pinicola mushrooms. Assume a population standard deviation of cadmium levels in Bolefus pinicola mushrooms of 0.37ppm.

Short Answer

Expert verified

Sample mean is 0.5258

99%confidence level of μis(0.2508,0.8008)

Step by step solution

01

Given Information

Population standard deviation is 0.37.

Data of twelve individuals are given:

02

Determination of sample mean

We are given that

i=112xi=6.31

Hence, sample meanx¯=1n×i=1nxi=112×6.31=0.5258

03

Determination of confidence interval

99%confidence level of μ=100×0.99%

1-α=0.99

role="math" localid="1652722332964" α=0.01

99%confidence level of μis calculated as

x¯-z0.005×σn,x¯+z005×σn

Now,

role="math" localid="1652722501303" x-z0.005×σn=0.5258-2.575×0.3712

role="math" localid="1652722561196" =0.5258-0.275

=0.2508

Also,

role="math" localid="1652722574315" x¯+z0.005×σn=0.5258+0.275

=0.8008

Hence, confidence interval ofμis(0.2508,0.8008)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

One-Sided One-Mean z-Intervals. Presuming that the assumptions for a one-mean z-interval are satisfied, we have the following formulas for (1-α)-level confidence bounds for a population mean \(\mu\) :

- Lower confidence bound: x~-zσ·σ/n

- Upper confidence bound: x¯+zα·σ/n

Interpret the preceding formulas for lower and upper confidence bounds in words.

What is a confidence interval estimate of a parameter? Why is such an estimate superior to a point estimate?

Keep on Rolling. The Rolling Stones, a rock group formed in the 1960s, have toured extensively in support of new albums, Pollstar has collected data on the earnings from the Stones's North American tours. For thirty randomly selected Rolling Stones concerts, the mean gross earnings is \(2.27 million. Assuming a population standard deviation gross earnings of \)0.5 million, obtain a 99% confidence interval for the mean gross earnings of all Rolling Stones concerts. Interpret your answer in words.

Political Prisoners. A. Ehlers et al. studied various characteristics of political prisoners from the former East Germany and presented their findings in the paper "Posttraumatic Stress Disorder (PTSD) Following Political Imprisonment: The Role of Mental Defeat. Alienation, and Perceived Permanent Change". According to the article. the mean duration of imprisonment for 32 patients with chronic PTSD was 33.4months. Assuming that σ=42months, determine a 95%confidence interval for the mean duration of imprisonment,μ. of all East German political prisoners with chronic PTSD. Interpret your answer in words.

A simple random sample is taken from a population and yields the following data for a variable of the population:

Find a point estimate for the population mean (i.e., the mean of the variable).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free