Suppose that you plan to apply the one-mean z-interval procedure to obtain a 90%confidence interval for a population mean, μYou know that σ=12 and that you are going to use a sample of size 9

a. What will be your margin of error?

b. What else do you need to know in order to obtain the confidence interval?

Short Answer

Expert verified

Part (a)6.5794

Part (b)(x¯-E,x¯+E)

Step by step solution

01

Part (a) Step 1: Given information

Population s.d.σ=12

Sample size n=9

02

Part (a) Step 2: Concept

The formula used:E=Zα/2×σn

03

Part (a) Step 3: Calculation

Population s.d.σ=12

Sample size n=9

Confidence level =90%=100×0.90%

1-α=0.90α=1-0.90α=0.10α/2=0.05

The margin of error, E, for a 100(1-α)% confidence interval is given by

E=Zα/2×σn

As a result, for a90% confidence interval, the margin of error is

E=Z0.05σn=1.645×129Z0.05=1.645=6.5794

04

Part (b) Step 1: Calculation

Because the confidence interval is given by (x¯-E,x¯+E), we need to know the sample mean x¯ to get the confidence interval.

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Most popular questions from this chapter

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