In below exercise:

a. obtain and interpret the quartiles.

b. determine and interpret the interquartile range.

c. find and interpret the five-number summary.

d. identify potential outliers, if any:

e. construct and interpret a boxplot.

The publication California Wild. Natural Sciences for Thinking Animals has monthly features called the "Sky Guide" that keeps track of the sunrise and sunset for the first day of each month in San Franciso. Over several issues, B. Quock from the Morrison Planetarium recorded the following sunrise times from July 1 of one year through June 1 of the next year. The times are given in minutes past midnight.

Short Answer

Expert verified

a) The quartiles are 364,398,426.5.The time of sunrise in 25%of this case is less than426.5minutes.

b) The interquartile range is 62.5.It means the middle 50%of sunrise is over 62.5minutes.

c) The five-number summary results observed that the variations between the quartiles are huge.

d) The data set remains within the limit. So there are no potential outliers.

e) From the boxplot we can see that there are no outliers. The boxplot is

Step by step solution

01

Step 1/9

Given Information:

The Morrison Planetarium recorded the following sunrise times from July 1 of one year through June 1 of the next year. The times are given in minutes past midnight.

02

Step 2/9

a) 'We find the quartiles as shown below:

First, we arrange the data in increasing order:

349352354374374396400400426427434445

The number of observations is 12.

The median will be

=(n+1)2=132=6.5

The median is the average of sixth and seventh position values; it can be shown in boldface in the ordered data set.

Hence, the second quartile of the data set is

Q2=396+4002=398

Therefore, the second quartile of the data set is398.

03

Step 3/9

Now, we consider the first part of the entire data set that lies at or below the median of the entire data set is

349352354374374396

The number of observations is 6.

The median will be

=(n+1)2=72=3.5

The median is the average of third and fourth position values; it can be shown in boldface in the ordered data set.

04

Step 4/9

The first quartile is

Q1=354+3742=364

Now we consider the second part of the exercise.

400400426427434445

The number of observations is 6.

The median will be

=(n+1)2=72=3.5

The median is the average of and position values.

The third quartile is

Q3=426+4272=426.5

Interpretation: From the above result we can observe that25% of the sunrise from July 1stof this year to June of next year is less than426.5 minutes.

05

Step 5/9

b) We find the interquartile range as shown below:

The interquartile range is obtained by finding the difference between the first and third quartile.

IQR=Q3Q1=426.5364=62.5

The 50%sunrise from July 1stof this year to the first of June of next year is over 62.5minutes.

06

Step 6/9

c) We find the five-number summary is shown below:

The minimum value in the data set is349.

The lower quartile of the data,Q1=364.

The median of the data set,Q2=398.

The upper quartile of the data,Q3=426.5.

The maximum value in the data set is445.

07

Step 7/9

The variation in the middle quarter is

=Q2Q1=398364=34

The variation in the third quarter is

=Q3-Q2=426.5398=28.5

The variation in the first quarter is

=Q1-Min=364349=15

The variation in the fourth quarter is

=MaxQ3=445426.5=18.5

From the results, we can observe that the variation between the quartiles is large.

08

Step 8/9

d) First we have to find the upper and lower limits.

Lower limit=Q11.5(IQR)=3641.5(62.5)=270.25Upper limit=Q3+1.5(IQR)=426.5+1.5(62.5)=520.25

Potential outliers are values below the lower limit and above the upper limit. All the data set remains within the limit of the results we got. So there are no potential outliers.

09

Step 9/9

e) Using MINITAB, the boxplot for the given data is shown below

There are no outliers.

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