In Exercises , we 3.65-3.70have provided simple data sets for you to practice the basics of finding measures of variation . For each data set determine.

a) Range

b) sample standard deviation

2,5,0,-1

Short Answer

Expert verified

a)Range=6b)samplestandarddeviation=2.6458

Step by step solution

01

Step 1. Given information. 

We have given data :2,5,0,-1

02

Step 2. Range of the data.  

Range=Max.value-Min.valueRange=5-(-1)Range=5+1Range=6

03

Step 3. Mean of the data.   

{x-x)2n-1Mean,x=xnMean=2+5+0+(-1)4Mean=64Mean=1.5sampiesize,n=4

04

Step 4. Standard deviation of the data.  

Variable x
Deviation from mean x-x
Squared deviation (x-x)2
2
0.5
0.25
5
3.5
12.25
0
-1.5
2.25
-1
-2.5
6.25


21.0

Thus, the standard deviation is

s=(x1-x)2n-1=21.04-1=7=2.6458

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