Consider the linear equation $y=4-3x$.

a. At what $y$-value does its graph intersect the $y$-axis?

b. At what $x$-value does its graph intersect the $y$-axis?

c. What is its slope?

d. By how much does the y-value on the line change when the $x$-value increases by $1$unit?

e. By how much does the $y$-value on the line change when the $x$value decreases by 2 units?

Given in the question that, Consider the linear equation $y=4-3x$.

We need to find that at what $y$-value does its graph intersect the $y$-axis

Consider the $y=4-3x$equation.

When the graph crosses the $y$- axis, $x=0$

$y=4-3\left(0\right)$

$y=4$

As a result, at $y=4$, the provided equation's graph intersects the $y$- axis.

Given in the question that, Consider the linear equation $y=4-3x$.

We need to find that at what $x$-value does its graph intersect the $y$-axis

$y=4-3x$is an equation.

Consider the $y=4-3x$equation.

When the graph crosses the $y$- axis, $x=0$.

As a result, at $x=0$, the following equation's graph intersects the $y$- axis.

Given in the question that, consider the linear equation $y=4-3x$.

We need to find its slope.

The formula$y=4-3x$

Calculation:

Consider the $y=4-3x$equation.

Compare $y=mx+c$

$m=-3$

to the above equation.

Thus, slope $=-3$.

Given in the question that,

consider the linear equation $y=4-3x$.

We need to find that by how much does the y-value on the line change when the $x$-value increases by 1 unit

$y=4-3x$is an equation.

Consider the equation $y=4-3x$for a moment.

The equation's slope is $=-3$.

slope $=\frac{\text{change in}y\text{-coordinates}}{\text{changeinx-coordinates}}$

$-3=\frac{\text{change in}\mathrm{y}\text{-coordinates}}{1}$

As a result, the $y$value changes. $=3$units

Given in the question that, consider the linear equation $y=4-3x$.

We need to find that by how much does the $y$-value on the line change when the $x$-value decreases by 2 units?

$y=4-3x$is an equation.

Consider the equation $y=4-3x$for a moment.

The equation's slope is $=-3$.

$=\frac{\text{change in}y\text{-coordinates}}{\text{changeinx-coordinates}}$

$-3=\frac{\text{change in}\mathrm{y}\text{-coordinates}}{2}$

Change in y=$6$

As a result, the change in $y-$value $=6$units.