Refer to Exercise 9.19. Explain what each of the following would mean.

(a) Type I error.

(b) Type II error.

(c) Correct decision.

Now suppose that the results of carrying out the hypothesis test lead to the rejection of the null hypothesis. Classify that conclusion by error type or as a correct decision if in fact the mean length of imprisonment for motor-vehicle-theft offenders in Sydney.

(d) equals the national mean of 16.7 months.

(e) differs from the national mean of 16.7 months.

Short Answer

Expert verified

(a) Rejecting a Null Hypothesis, when it is true.

(b) Rejecting a Null Hypothesis, when H0is false.

(c) If the true null hypothesis is not rejected or a false null hypothesis is rejected.

(d) Correct Decision.

(e) Type II error.

Step by step solution

01

Step 1. Given Information.

The null hypothesis is,

H0:μ=16.7months.

The alternative hypothesis is,

H0:μ16.7 months.

02

Part (a). Type I error

According to the definition of the type I error it is to reject a null hypothesis when it is true. A type I error would occur in fact H0:μ=16.7monthstrue, that is the mean length of imprisonment for motor-vehicle-theft offenders in Australia is 16.7months but the result of the sampling lead to conclude that the mean length of imprisonment for motor-vehicle-theft offenders in Australia is less than16.7months.

03

Part (b). Type II error.

According to the definition of the type II error, it is to not reject a null hypothesis when it H0is false. A type II error would occur in fact μ=16.7months is not to be rejected, but the results of the sampling fall to lead to conclude that the mean length of imprisonment for motor-vehicle-theft offenders is in 16.7months.

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Most popular questions from this chapter

We have been provided a sample mean, sample size, and population standard deviation. In the given case, use the one-mean z-test to perform the required hypothesis test at the 5% significance level.

x¯=23,n=24,σ=4,H0:μ=22,Ha:μ22

The normal probability curve and stem-to-leaf diagram of the data are shown in figure; σis known.

Perform Hypothesis test for mean of the population from which data is obtained and decide whether to use z-test, t-test or neither. Explain your answer.

In each of Exercises 9.41-9.46 ,determine the critical values for a one-mean z-test. For each exercise, draw a graph that illustrates your answer

A left-tailed test withα=0.05

9.95 Two-Tailed Hypothesis Tests and CIs. As we mentioned on page 378 , the following relationship holds between hypothesis tests and confidence intervals for one-mean z-procedures: For a two-tailed hypothesis test at the significance level α, the null hypothesis H0:μ=μ0 will be rejected in favor of the alternative hypothesis Ha:μμ0if and only if μ0 lies outside the (1-α)-level confidence interval for μ. In each case, illustrate the preceding relationship by obtaining the appropriate one-mean z-interval (Procedure 8.1 on page 322 ) and comparing the result to the conclusion of the hypothesis test in the specified exercise.
a. Exercise 9.84
b. Exercise 9.87

Cheese Consumption. Refer to Problem 24. The following table provides last year's cheese consumption: in pounds, 35 randomly selected Americans.

4629333842403433323628472642363245243928334433263727313637373622443629

  1. At the 10%significance level, do the data provide sufficient evidence to conclude that last year's mean cheese consumption for all Americans has increased over the 2010 mean? Assume that σ=6.9lb. Use a z-test. (Note: The sum of the data is 1218lb.)
  2. Given the conclusion in part (a), if an error has been made, what type must it be? Explain your answer.
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