We have been provided a sample mean, sample size, and population standard deviation. In the given case, use the one-mean z-test to perform the required hypothesis test at the 5% significance level.

x¯=24,n=15,σ=4,H0:μ=22,Ha:μ>22

Short Answer

Expert verified

The value of z is 1.94, critical value is 1.645,P=0.026and reject H0.

Step by step solution

01

Step 1. Given information.

Consider the given question,

x¯=24,n=15,σ=4,H0:μ=22,Ha:μ>22

02

Step 2. Consider the test hypothesis.

Consider the given hypothesis,

μis the population mean.

The test hypothesis is given below,

H0:μ=22VsHa:μ>22

Therefore, the test is right tailed test.

And the level of significance isα=0.05.

03

Step 3. Use the test statistics.

We want to find the hypothesis test about the mean μ,

z=x¯-μ0σn=24-22415=1.94

Therefore, this is right tailed test with α=0.05, the critical value is given below,

role="math" localid="1651164260948" za=z0.05=1.645

The rejection region is z>z0.05.

Here, z=1.94>z0.05=1.645

Hence, we reject H0at 5% level of significance as the value of the test satisfice falls in the rejection region.

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Most popular questions from this chapter

Refer to Exercise 9.15. Explain what each of the following would mean.

(a) Type I error

(b) Type II error

(c) Correct decision

Now suppose that the results of carrying out the hypothesis test lead to nonrejection of the null hypothesis. Classify that conclusion by error type or as a correct decision if in fact the mean cadmium level in Boletus Pinicolamushrooms.

(d) equals the safety limit of 0.5ppm.

(e) exceeds the safety limit of0.5ppm.

Data on salaries in the public school system are published annually in Ranking of the States and Estimates of School Statistics by the National Education Association. The mean annual salary of (public) classroom teachers is $55.4thousand. A hypothesis test is to be performed to decide whether the mean annual salary of classroom teachers in Ohio is greater than the national mean.

The following relationship holds between hypothesis tests and confidence intervals for one-mean t-procedures: For a two-tailed hypothesis test at the significance level α, the null hypothesis H0:μ=μ0will be rejected in favor of the alternative hypothesis Ha:μ>μ0if and only if μ0lies outside the 1-α-level confidence interval for μ. In each case, illustrate the preceding relationship by obtaining the appropriate one-mean t-interval and comparing the result to the conclusion of the hypothesis test in the specified exercise.

Part (a): Exercise 9.113

Part (b): Exercise 9.116

As we mentioned on page \(378\), the following relationship holds between hypothesis tests and confidence intervals for one mean \(z-\)procedures: For a two-tailed hypothesis test at the significance level \(\alpha\), the null hypothesis \(H_{0}:\mu =\mu_{0}\) will be rejected in favor of the alternative hypothesis \(H_{a}:\mu \neq \mu_{0}\) if and only if \(\mu_{0}\) lies outside the \((1-\infty)\) level confidence interval for \(\mu\). In each case, illustrate the preceding relationship by obtaining the appropriate one-mean \(z-\)interval and comparing the result to the conclusion of the hypothesis test in the specified exercise.

a. Exercise \(9.84\)

b. Exercise \(9.87\)

According to the Bureau of Crime Statistics and Research of Australia, as reported on Lawlink, the mean length of imprisonment for motor-vehicle-theft offenders in Australia is 16.7 months. One hundred randomly selected motor-vehicle-theft of-fenders in Sydney, Australia, had a mean length of imprisonment of 17.8 months. At the 5% significance level, do the data provide sufficient evidence to conclude that the mean length of imprisonment for motor-vehicle-theft offenders in Sydney differs from the national mean in Australia? Assume that the population standard deviation of the lengths of imprisonment for motor-vehicle-theft offenders in Sydney is6months.

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