Dementia is the loss of the in actual and social abilities severe enough to interfere with judging behavior and daily functioning. Alzheimer's disease is the most common type of dementia. In the article "Living with Early Onsite dementia: Exploring the Experience and Developing Evidence Guidelines for Practice", P Harris and J Keady explored the experiment struggles of people diagnosed with dementia and their familiar simple random sample \(21\) people with early-onset dementia the following data on age at diagnosis in years.

At the \(1%\) significance level, do the data provide sufficient evidence to conclude that the mean age at diagnosis of all people with early onset dementia is less than \(55\) years old? Assume that the population is standard deviation is \(6.8\) years.

Short Answer

Expert verified

The null hypothesis is not rejected and it is reasonable to believe that the mean age at diagnosis of all people with early dementia is less than \(55\) year old.

Step by step solution

01

Step 1. Given information

The standard deviation is \(68\), the mean is \(52.5\), the sample size is \(21\) and the level of significance is \(0.01\).

02

Step 2. Calculation

The hypothesis are,

\(H_{0}:\mu =55\)

\(H_{0}:\mu <55\)

The test statistics is,

\(z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}\)

Substitute the given values in above equation.

\(z=\frac{52.5-55}{\frac{6.8}{\sqrt{21}}}\)

\(=-1.68\)

The critical value for level of significance of \(0.01\) is \(-2.33\)

The graph is shown below.

Since, \(z>z_{0.025}\)

Thus, the null hypothesis is not rejected and it is reasonable to believe that the mean age at diagnosis of all people with early dementia is less than \(55\) year old.

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Most popular questions from this chapter

The normal probability curve and stem-to-leaf diagram of the data are shown in figure; σis unknown.

Perform Hypothesis test for mean of the population from which data is obtained and decide whether to use z-test, t-test or neither. Explain your answer.

In Exercise 8.146 on page 345, we introduced one-sided one-mean t-intervals. The following relationship holds between hypothesis tests and confidence intervals for one-mean t-procedures: For a left-tailed hypothesis test at the significance level α, the null hypothesis H0:μ=μ0will be rejected in favor of the alternative hypothesis Ha:μ<μ0if and only if μ0is greater than or equal to the 1-α- level upper confidence bound for μ. In each case, illustrate the preceding relationship by obtaining the appropriate upper confidence bound and comparing the result to the conclusion of the hypothesis test in the specified exercise.

Part (a): Exercise 9.117

Part (b): Exercise 9.118

College Basketball and particularly the NCAA basketball tournament is a popular venue for gambling, from novices in office betting pools to high rollers. To encourage uniform betting across teams. Las Vegas oddsmakers assign a point spread to each game. The point spread is the oddsmakers prediction for the number of points by which the favored team will win. If you bet on the favorite, you win the bet provided the favorite wins by more than the point spread; otherwise you lose the bet. Is the point spread a good measure of the relative ability of the two teams? They obtained the difference between the actual margin of victory and the point spread, called the point-spread error for \(2109\) college basketball games. The mean-point spread error was found to be \(-0.2\) point with a standard deviation of \(10.9\) points. For a particular game, a point spread error of \(0\) indicates that the point was a perfect estimate of the two teams relative abilities.

a. If on average the oddsmakers are estimating correctly, what is the (population) mean point-spread error?

b. Use the data to decide, at the \(5%\) significance level, whether the (population) mean point-spread error differs from \(0\).

c. Interpret your answers in part (b).

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a. Decide whether, on average, the net percentage gain for jobs exceeds 0.2. Assume a population standard deviation of 0.42. Apply the one-mean z-test with a 5% significance level.
b. Obtain a normal probability plot, boxplot, histogram, and stem-and-leaf diagram of the data.
c. Remove the outliers (if any) from the data and then repeat part (a).
d. Comment on the advisability of using the z-test here.

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a. Obtain a normal probability plot, a boxplot, a histogram, and a stem-and-leaf diagram of the data on beef consumptions.

b. Decide, at the 5% significance level, whether last year's mean beef consumption is less than the 2011 mean of 57.5 lb. Apply the one mean t-test.

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d. Assuming that the four potential outliers are not recording errors, comment on the advisability of removing them from the sample data before performing the hypothesis test.

e. What action would you take regarding this hypothesis test?

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