Buckling Up. Refer to Exercise 11.109and find and interpret a 99%confidence interval for the difference between the proportions of seat-belt users for drivers in the age groups 16-24 years and 25-69 years.

Short Answer

Expert verified

There is 99% interval for the difference between the proportion is (-0.0937,-0.0063)

Step by step solution

01

Given Information

The given values are,

n1=1000,n2=1100,p~1=0.790,p~2=0.840.

02

Explanation

The formula for z, is given by,

z=p~1-p~2p~p1-p~p1n1+1m2

The required value ofza2with 99%confidence level is 2.575.

The 98%confidence interval is.

p~1-p~2±za2p~11-p~1n1+p~11-p~1n2=(0.790-0.840)

±2.5750.790(1-0.790)1000+0.840(1-0.840)1100

=-0.05±0.0437

=(-0.0937,-0.0063)

Therefore, there is 99%interval for the difference between the proportion is (-0.0937,-0.0063)

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Margin of error=0.03

Confidence level=99%

Educated guess=0.5

(a) Obtain a sample size that will ensure a margin of error of at most the one specified (provided of course that the observed value of the sample proportion is further from 0.5that of the educated guess.

(b). Compare your answer to the corresponding one and explain the reason for the difference, if any.

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