In this Exercise, we have given the number of successes and the sample size for a simple random sample from a population. In each case,

a. use the one-proportion plus-four z-interval procedure to find the required confidence interval.

b. compare your result with the corresponding confidence interval found in Exercise 11.25-11.30, if finding such a confidence interval was appropriate.

role="math" localid="1651325715651" x=8,n=40,95%level

Short Answer

Expert verified

(a) The one-proportion z-interval technique is adequate because xand n-xare both 5or more.

(b) It is possible to be 95%convinced that the confidence interval is between 0.076and 0.324.

Step by step solution

01

Part(a) Step 1: Given Information

The size of a simple random sample from a population, as well as the number of successes.

x=8,n=40,95%level

n-x=40-8=32, here xand n-xare both 5or greater.

02

Part(a) Step 2: Explanation

The sample proportion p'=xnis calculated from the data.

840=0.2

03

Part(b) Step 1: Given Information

The size of a simple random sample from a population, as well as the number of successes.

x=8,n=40,95%level

n-x=40-8=32, here xand n-x are both 5 or greater.

04

Part(b) step 2: Explanation

The confidence interval is 95%, which means α=0.05.

It is discovered thatlocalid="1651326317744" za/2=z0.05/2=1.96

The pconfidence interval is of the form

p'-zaα/2p'1-p'ntop'+za/2p'1-p'n

i.e. localid="1651326715537" 0.2-1.960.2(1-0.2)40to0.2+1.960.2(1-0.2)40

i.e. localid="1651326727514" 0.2-0.124to0.2+0.124

i.e.localid="1651326739386" 0.076to0.324

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Most popular questions from this chapter

Getting a Job. The National Association of Colleges and Employers sponsors the Graduating Student and Alumni Survey. Part f the survey gauges student optimism in landing a job after graduation. According to one year's survey results, published in American Demographics, the 1218respondents, 733 said that they expected difficulty finding a job. Note: In this problem and the next, round your proportion answers to four decimal places.

a. Use these data to find and interpret a 95% confidence interval for the proportion of students who expect difficulty finding a job.

b. Find the margin of error for the estimate of p.

c. Express the confidence interval in the form point estimate ± margin of error.

Obtain a sample size that will ensure a margin of error of at most the one specified.

Margin of error=0.02

Confidence level=95%

In this Exercise, we have given the number of successes and the sample size for a simple random sample from a population. In each case,

a. use the one-proportion plus-four z-interval procedure to find the required confidence interval.

b. compare your result with the corresponding confidence interval found in Exercise 11.25-11.30, if finding such a confidence interval was appropriate.

role="math" localid="1651327118166" x=35,n=50,99%level

What important theorem in statistics implies that, for a large sample size, the possible sample proportions of that size have approximately a normal distribution?

11.96 Kids Attending Church. In an ABC Global Kids Study, conducted by Roper Starch Worldwide, Inc., estimates were made in various countries of the percentage of children who attend church at least once a week. Two of the countries in the survey were the United States and Germany. Considering these two countries only,
a. identify the specified attribute.
b. identify the two populations.
c. What are the two population proportions under consideration?

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