Indicted Governor. On Thursday, June 13, 1996, thenArizona Governor Fife Symington was indicted on 23counts of fraud and extortion. Just hours after the federal prosecutors announced the indictment, several polls were conducted of Arizonans asking whether they thought Symington should resign. A poll conducted by Research Resources, Inc., that appeared in the Phoenix Gazette, revealed that 58%of Arizonans felt that Symington should resign; it had a margin of error of plus or minus 4.9 percentage points. Another poll, conducted by Phoenix-based Behavior Research Center and appearing in the Tempe Daily News, reported that 54% of Arizonans felt that Symington should resign; it had a margin of error of plus or minus 4.4 percentage points. Can the conclusions of both polls be correct? Explain your answer.

Short Answer

Expert verified

It's possible that the results of both polls are correct.

Step by step solution

01

Given Information

In a poll conducted by Research Resource Inc reported that 58%(with a margin of error of plus or minus 4.9%points of Arizonians felt that Governor Symington should resign.

In a second poll conducted by Behavior Research Center, reported that 54%(with a margin of error of plus or minus

4.4%points of Arizonians felt that Governor Symington should resign.

02

Explanation

Assume that both surveys utilized a confidence level of 95%.

As a result, both polls give the percentage/proportion of Arizonians who believe Governor Symington should resign at a 95%confidence level.

According to the data, the Research Resource Inc poll's confidence interval ranges from 53.1%to 62.9%(58±4.9).

The Behavior Research Center's confidence interval is 49.6% to 58.4% (54±4.4).

It should be noticed that both surveys give common credible results ranging from 53.1% to 58.4%.

As a result, it's feasible that the conclusions of both polls are right.

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Most popular questions from this chapter

Obtain a sample size that will ensure a margin of error of at most the one specified.

Margin of error=0.02

Confidence level=90%

In this Exercise, we have given the number of successes and the sample size for a simple random sample from a population. In each case,

a. use the one-proportion plus-four z-interval procedure to find the required confidence interval.

b. compare your result with the corresponding confidence interval found in Exercise 11.25-11.30, if finding such a confidence interval was appropriate.

role="math" localid="1651325715651" x=8,n=40,95%level

We have given a likely range for the observed value of a sample proportion p^

0.7orless

a. Based on the given range, identify the educated guess that should be used for the observed value of p^to calculate the required sample size for a prescribed confidence level and margin of error.

b. Identify the observed values of the sample proportion that will yield a larger margin of error than the one specified if the educated guess is used for the sample-size computation.

Buckling Up. Refer to Exercise 11.109and find and interpret a 99%confidence interval for the difference between the proportions of seat-belt users for drivers in the age groups 16-24 years and 25-69 years.

In discussing the sample size required for obtaining a confidence interval with a prescribed confidence level and margin of error, we made the following statement: "If we have in mind a likely range for the observed value of p^, then, in light of Fig. 11.1, we should take as our educated guess for p^the value in the range closest to 0.5"Explain why.

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