Breastmilk and Antioxidants.There is convincing evidence that breastmilk containing antioxidants is important in the prevention of diseases in infants. Researchers A. Xavier et al. studied the effects of storing breastmilk on antioxidant levels in the article "Total Antioxidant Concentrations of Breastmilk-An Eye-Opener to the Negligent" (Journal of Health, Population and Nutrition, Vol. 29, No. 6, pp. 605-611). Samples of breastmilk were taken from women and divided into fresh samples that were immediately tested and the remaining samples that were stored in the refrigerator and tested after 48 hours. A hypothesis test is to be performed to decide whether, on verage, stored breastmilk has a lower total antioxidant capacity.

a. identify the variable.

b. identify the two populations:

c. identify the pairs

d. identify the paired-diffenence variable.

e. determine the null and allernative hypotheses.

f. classify the hypothesis test as nwo tailed, left tailed, or right tailed.

Short Answer

Expert verified

Part a), the variable is "total antioxidant capacity"

Part b) the two populations in the study are "fresh breastmilk" and "stored breastmilk".

Part c)the pair is a "women stored breastmilk and fresh breastmilk"

Part d)the difference between the antioxidant capacity of stored breastmilk and the antioxidant capacity of fresh breastmilk".

Part e)Definition provided

Part f) the hypotheses test as left tailed test

Step by step solution

01

Step 1:Given information

Breastmilk and Antioxidants.There is convincing evidence that breastmilk containing antioxidants is important in the prevention of diseases in infants. Researchers A. Xavier et al. studied the effects of storing breastmilk on antioxidant levels in the article "Total Antioxidant Concentrations of Breastmilk-An Eye-Opener to the Negligent" (Journal of Health, Population and Nutrition, Vol. 29, No. 6, pp. 605-611). Samples of breastmilk were taken from women and divided into fresh samples that were immediately tested and the remaining samples that were stored in the refrigerator and tested after 48 hours. A hypothesis test is to be performed to decide whether, on verage, stored breastmilk has a lower total antioxidant capacity.

02

Step 2:Explaination a)

Identify the variable in the study.

A variable is an attribute or the characteristic that can be measured. The value of the variable may differ for each and every unit. That is, a variable is defined as the characteristic which is recorded for each case.

From the given description, the variable is "total antioxidant capacity" because the outcome for each attempt can be measured and this value may vary for each and every attempt.

03

Step 2:Explaination b)

Identify the two populations:

Population:

The population is the complete set of people who are considered for the study.

Therefore, the two populations in the study are "fresh breastmilk" and "stored breastmilk".

04

Step 2:Explaination c)

Identify the pairs.

Here, the pair is a "women stored breastmilk and fresh breastmilk" because the samples of breastmilk taken from women and divided into fresh breastmilk and stored breastmilk.

05

Step 2:Explaination d)

Identify the paired difference variable.

The paired difference variable is "the difference between the antioxidant capacity of stored breastmilk and the antioxidant capacity of fresh breastmilk". That is,

Paired difference variable=Antioxidant capacity of stored breastmilk -Antioxidant capacity of stored breastmilk

06

Step 2:Explaination e)

State the null and alternative hypotheses.

Null hypothesis:

H0:μS=μF

That is, there is no between the antioxidant capacity of stored breastmilk and the antioxidant capacity of fresh breastmilk.

Alternative hypothesis:

Ha:μs<μF

That is, the antioxidant capacity of stored breastmilk is less than the antioxidant capacity of fresh breastmilk.

07

Step 2:Explaination f)

Classify the hypotheses test as two tailed, left tailed, or right tailed.

From part (e), it is clear that the hypotheses test as left tailed test because the antioxidant capacity of stored breastmilk is less than the antioxidant capacity of fresh breastmilk.

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Most popular questions from this chapter

V. Tangpricha et al. did a study to determine whether fortifying orange juice with Vitamin D would result in changes in the blood levels of five biochemical variables. One of those variables was the concentration of parathyroid hormone (PTH), measured in picograms/milliliter ( pg/ml ). The researchers published their results in the paper "Fortification of Orange Juice with Vitamin D: A Novel Approach for Enhancing Vitamin D Nutritional Health" (American Journal of Clinical Nutrition, Vol. 77, pp. 1478-1483). Concentration levels were recorded at the beginning of the experiment and again at the end of 12weeks. The following data, based on the results of the study, provide the decrease (negative values indicate an increase) in PTH levels, in pg/ml, for those drinking the fortified juice and for those drinking the unfortified juice.

At the 5% significance level, do the data provide sufficient evidence to conclude that drinking fortified orange juice reduces PTH level more than drinking unfortified orange juice? (Note: The mean and standard deviation for the data on fortified juice are 9.0pg/mL and 37.4pg/mL, respectively, and for the data on unfortified juice, they are 1.6pg/mLand34.6pg/mL, respectively.)

Suppose that you want to perform a hypothesis test to compare the means of two populations, using independent simple random samples. Assume that the two distributions (one for each population) of the variable under consideration are normally distributed and have equal standard deviations. Answer the following questions and explain your answers.

a. Is it permissible to use the pooled t-test to perform the hypothesis test?

b. Is it permissible to use the Mann-Whitney test to perform the hypothesis test?

c. Which procedure is preferable, the pooled t-test or the Mann-Whitney test?

Suppose that the sample sizes, n4and n2, are equal for independent simple random samples from two populations.

a. Show that the values of the pooled and nonpooled r-statistics will be identical. (Hint: Refer to Exercise 10.61 on page 417.)

b. Explain why part (a) does not imply that the two t-tests are Equivalent (i.e., will necessarily lead to the same conclusion) when the sample sizes are equal.

In each of Exercises 10.35-10.38, we have provided summary statistics for independent simple random samples from two populations. Preliminary data analyses indicate that the variable under consideration is normally distributed on each population. Decide, in each case, whether use of the pooled t-lest and pooled t-interval procedure is reasonable. Explain your answer.
10.35 x¯1=468.3,s1=38.2,n1=6

x2=394.6,s2=84.7,n2=14

In each of exercise 10.13-10.18, we have presented a confidence interval for the difference,μ1-μ2, between two population means. interpret each confidence interval

99%CI from-10to5

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